Leetcode题目总结

题目: Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each n

为了进好公司这一个多月就得抽时间刷leetcode了..感觉这个OJ很不严谨...好多边界条件都没说清处..不过还好可以推测.唯一的好处就是不用自己编译调试,可以直接在网上显示出结果.当然,复杂一点的题目为了调试自己构建题目的结构也是很麻烦的...所以我发现提交里面错误好多.....再就是在笔记本上会时不时的变卡...每次提交都得等个3,4分钟才成功.要不就502错误... 我的题目按照通过率来.从通过率最高的题目开始讲解.每题不一定是最优解,都是我想得.仅供参考. 题目标题我都标好了.可以用c

又刷了30题了,这速度还不错.因为还有别的东西要复习,所以进度并不快.感觉还是能学到很多新东西的.早知道这个就不用去其他地方刷了.这个难度不高,还可以知道哪些情况没考虑.比其他OJ那种封闭式的好多了.还是进入正题吧. 1.Rotate Image 这个做过两三次了,但每次还是得重新开始推导..这次又推导了很久..不过好在做过,代码也写得比较简洁. 主要思路就是第一层循环按层次深入.第二层把旋转后对应替代的4个位置循环更新.swap就是用来更新用的.做完发现讨论里的最高票代码就是我这样子= =  

题目一: Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], ["a","a",

题目一: Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. An example is the root-to-leaf path 1->2->3 which represents the number 123. Find the total sum of all root-to-leaf numbers. For example, 1 /

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路: 主要是深层复制的问题: 本题比较简单,具体实现见代码: /** * Definition for singly-linked list with a ran

题目: Write a function that takes a string as input and reverse only the vowels of a string. Example 1: Given s = "hello", return "holle". Example 2: Given s = "leetcode", return "leotcede". 题目解答: 要求将字符串中所有的元音字母逆转,辅音字

这同样也是一道LeetCode Online Judge上面的题目,属于easy级别,原题如下: 题目 Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element alw

Populating Next Right Pointers in Each Node Given a binary tree struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; } Populate each next pointer to point to its next right node. If there is no next right node, the next

题目: Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note:You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements i