Oracle 中分组排序取值的问题

整理一下排序：

建表语句：create table EXAM(  name    VARCHAR2(32),  subject VARCHAR2(32),  score   INTEGER)数据：INSERT INTO EXAM VALUES (‘赵柳‘, ‘数学‘, ‘71‘);INSERT INTO EXAM VALUES (‘张三‘, ‘数学‘, ‘81‘);INSERT INTO EXAM VALUES (‘李四‘, ‘数学‘, ‘75‘);INSERT INTO EXAM VALUES (‘起点‘, ‘数学‘, ‘88‘);INSERT INTO EXAM VALUES (‘起点‘, ‘英语‘, ‘98‘);INSERT INTO EXAM VALUES (‘李四‘, ‘英语‘, ‘86‘);INSERT INTO EXAM VALUES (‘赵柳‘, ‘英语‘, ‘86‘);INSERT INTO EXAM VALUES (‘张思‘, ‘英语‘, ‘33‘);INSERT INTO EXAM VALUES (‘李四‘, ‘语文‘, ‘75‘);INSERT INTO EXAM VALUES (‘张三‘, ‘语文‘, ‘81‘);INSERT INTO EXAM VALUES (‘赵柳‘, ‘语文‘, ‘71‘);INSERT INTO EXAM VALUES (‘起点‘, ‘语文‘, ‘88‘);

1.row_number() over() 的用法：SELECT *,ROW_NUMBER() OVER(PARTITION BY ‘分组‘ ORDER BY ‘排序‘) RN FROM TABLE;SELECT t.name,t.subject,t.score, row_number() OVER (PARTITION BY t.subject ORDER BY t.score DESC) rn FROM exam t ;2：rank() over()跳跃排序对于row_number() over() 来说，如果两个值相等，区分不出前后，如下图所示：

是跳跃排序的，是可以有两个第二名的，后面跟着第三名；

SELECT t.name,t.subject,t.score, rank() OVER (PARTITION BY t.subject ORDER BY t.score DESC) rn FROM exam t ;

3：dense_rank() over()

如果想 两个第二名之后跟着是第三名：SELECT t.name,t.subject,t.score, dense_rank() OVER (PARTITION BY t.subject ORDER BY t.score DESC) rn FROM exam t ;

原文地址：https://www.cnblogs.com/wangjianly/p/9313581.html