360. Sort Transformed Array二元一次方程返回大数序列

[抄题]:

Given a sorted array of integers nums and integer values ab and c. Apply a quadratic function of the form f(x) = ax2 + bx + c to each element x in the array.

The returned array must be in sorted order.

Expected time complexity: O(n)

Example 1:

Input: nums = [-4,-2,2,4], a = 1, b = 3, c = 5
Output: [3,9,15,33]

Example 2:

Input: nums = [-4,-2,2,4], a = -1, b = 3, c = 5
Output: [-23,-5,1,7]

[暴力解法]:

时间分析:

空间分析:

[优化后]:

时间分析:

空间分析:

[奇葩输出条件]:

[奇葩corner case]:

[思维问题]:

不知道和指针对撞有啥关系:谁的平方比较大(绝对值大)数组就先加谁

[英文数据结构或算法,为什么不用别的数据结构或算法]:

[一句话思路]:

[输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入):

[画图]:

[一刷]:

[二刷]:

[三刷]:

[四刷]:

[五刷]:

[五分钟肉眼debug的结果]:

[总结]:

[复杂度]:Time complexity: O() Space complexity: O()

[算法思想:迭代/递归/分治/贪心]:

[关键模板化代码]:

[其他解法]:

[Follow Up]:

[LC给出的题目变变变]:

[代码风格] :

[是否头一次写此类driver funcion的代码] :

[潜台词] :

原文地址:https://www.cnblogs.com/immiao0319/p/9461599.html

时间: 2024-10-11 22:16:40

360. Sort Transformed Array二元一次方程返回大数序列的相关文章

360. Sort Transformed Array

Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f(x) = ax2 + bx + c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums = [-4, -2,

Leetcode 360: Sort Transformed Array

Given a sorted array of integers nums and integer values a, b and c. Apply a quadratic function of the form f(x) = ax2 + bx + c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums =

leetcode360 - Sort Transformed Array - medium

Given a sorted array of integers nums and integer values a, b and c. Apply a quadratic function of the form f(x) = ax2 + bx + c to each element x in the array.The returned array must be in sorted order.Expected time complexity: O(n)Example 1:Input: n

Sort Transformed Array

Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f(x) = ax2 + bx + c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums = [-4, -2,

[LeetCode] Sort Transformed Array 变换数组排序

Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f(x) = ax2 + bx + c to each element x in the array. The returned array must be in sorted order. Expected time complexity: O(n) Example: nums = [-4, -2,

Sort the Array

Being a programmer, you like arrays a lot. For your birthday, your friends have given you an array a consisting of n distinct integers. Unfortunately, the size of a is too small. You want a bigger array! Your friends agree to give you a bigger array,

js实现求二元一次方程的根

已知ax的平方+bx+c=0;求根:<br />系数A:<input type="number" id="a" /><br />系数B:<input type="number" id="b" /><br />系数C:<input type="number" id="c" /><br /><input

二元一次方程组求解

首先要找到二元一次方程组的通解,例如: ax+by=m cx+dy=n 不难算出 x=(md-bn)/(ad-bc) y=(mc-an)/(bc-ad) 程序代码: #include<stdio.h> #include<math.h> int main(){ int a,b,c,d,m,n; double x=0,y=0; scanf("%d,%d,%d,%d,%d,%d",&a,&b,&c,&d,&m,&n);

解不等式组、二元一次方程组、三元一次方程组

不等式性质: 一.加减同一个数,方向不变. 二.乘以(除以)同一个正数,方向不变. 三.乘以(除以)同一个负数,方向改变. 例:/3x - 15 > 0  ① \7x - 2 < 8x  ② 解①式可得 x > 5 解②可可得 -2 < x 该不等式的解集为 x > 5 解二元一次方程组: 1.消元解二元一次方程组有代入消元和加减消元法. 2.代入消元法:把二元一次方程组的一个未知数用另一个未知数表示出来,再带入另一个方程,实现消元. 3.加减消元法:两个方程中同一个未知数系