Description
People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ..., and 289-credit coins, are available in Silverland.
There are four combinations of coins to pay ten credits:
ten 1-credit coins,
one 4-credit coin and six 1-credit coins,
two 4-credit coins and two 1-credit coins, and
one 9-credit coin and one 1-credit coin.
Your mission is to count the number of ways to pay a given amount using coins of Silverland.
Input
The input consists of lines each containing an integer meaning an amount to be paid, followed by a line containing a zero. You may assume that all the amounts are positive and less than 300.
Output
For each of the given amount, one line containing a single integer representing the number of combinations of coins should be output. No other characters should appear in the output.
Sample Input
2
10
30
0
Sample Output
1 4 27
一个很标准的母函数题目,唯一需要改变的就是把+i写成+i*i 因为题意是平方倍的增加
#include<stdio.h> #include<iostream> using namespace std; int n; int a[301],b[301]; int main() { while(cin>>n) { if(n==0) break; for(int i=0;i<=n;i++) { a[i]=1; b[i]=0; } for(int i=2;i<=n;i++) { for(int j=0;j<=n;j++) { for(int k=0;k+j<=n;k+=i*i) { b[k+j]+=a[j]; } } for(int z=0;z<=n;z++) { a[z] = b[z]; b[z] = 0; } } cout<<a[n]<<endl; } return 0; }