本文介绍了Guava中Range的使用, 使用Range和Guava的函数式编程可以用少量代码实现指定范围内容的过滤。
import com.google.common.base.Function; import com.google.common.base.Predicate; import com.google.common.base.Predicates; import com.google.common.collect.Range; /** * Guava Range类使用 * Created by wenniuwuren on 2015/6/3. */ public class RangeTest { public static void main(String[] args) { Range<Integer> numberRange = Range.closed(1, 10); System.out.println("closed包含边界" + numberRange.contains(10) + " ," + numberRange.contains(1)); Range<Integer> numberOpenRange = Range.open(1, 10); System.out.println("open不包含边界" + numberOpenRange.contains(1) + ", " + numberOpenRange.contains(10)); Range<Integer> atLeast = Range.atLeast(10); System.out.println("大于等于边界的所有值" + atLeast); Range<Integer> lessThan = Range.lessThan(10); System.out.println("小于等于边界的所有值" + lessThan); /** * 过滤掉不符合内容Range范围的 */ Range<Integer> ageRange = Range.closed(35,50); Function<Person,Integer> ageFunction = new Function<Person, Integer>() { @Override public Integer apply(Person person) { return person.getAge(); } }; Person p1 = new Person("zhangsan", 50); Person p2 = new Person("lisi", 70); Predicate<Person> predicate = Predicates.compose(ageRange, ageFunction); System.out.println("是否包含zhangsan:" + predicate.apply(p1) + ", 是否包含lisi:" + predicate.apply(p2)); } } class Person { private String name; private Integer age; public Person(String name, Integer age) { this.name = name; this.age = age; } public Integer getAge() { return age; } public void setAge(Integer age) { this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } }
输出结果:
参考资料:
《Getting Started with Google Guava》
时间: 2024-11-12 11:18:53