322. Coin Change(leetcode )

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, return -1.

Example 1:
coins = [1, 2, 5], amount = 11
return 3 (11 = 5 + 5 + 1)

Example 2:
coins = [2], amount = 3
return -1.

Note:
You may assume that you have an infinite number of each kind of coin.

Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.

求解是需要最少的硬币的数量。

dp这个容器是用来存储硬币的数量的。。

 1 class Solution {
 2 public:
 3     int coinChange(vector<int>& coins, int amount) {
 4         int ax = amount+1;
 5         vector<int>dp(amount+1,ax);
 6         dp[0]=0;
 7         for(int i=1;i<=amount;i++){
 8             for(int j=0;j<coins.size();j++){
 9                 if(coins[j]<=i)
10                 dp[i]=min(dp[i],dp[i-coins[j]]+1);
11             }
12         }
13         return dp[amount]>amount?-1:dp[amount];
14     }
15 };

原文地址：https://www.cnblogs.com/followyounger/p/8275364.html