A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than the node‘s key.
- The right subtree of a node contains only nodes with keys greater than or equal to the node‘s key.
- Both the left and right subtrees must also be binary search trees.
A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.
Output Specification:
For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.
Sample Input:
10 1 2 3 4 5 6 7 8 9 0
Sample Output:
6 3 8 1 5 7 9 0 2 4
给出一个序列,从小到大排序就是树的中序遍历,不妨中序遍历走一遍把各个结点放在各自的位置。由于是完全二叉树,可以用数组按顺序来存,完事输出数组就是层序遍历。
代码:
#include <stdio.h> #include <string.h> #include <stdlib.h> int n,l[1001],tr[2010],c; void inorder(int k) { if(k > n)return; inorder(k * 2); tr[k] = l[c ++]; inorder(k * 2 + 1); } void levelprint() { for(int i = 1;i <= n;i ++) { if(i == 1) printf("%d",tr[i]); else printf(" %d",tr[i]); } } int cmp(const void *a,const void *b) { return *(int *)a - *(int *)b; } int main() { scanf("%d",&n); for(int i = 0;i < n;i ++) scanf("%d",&l[i]); qsort(l,n,sizeof(l[0]),cmp); inorder(1); levelprint(); }
原文地址:https://www.cnblogs.com/8023spz/p/12259527.html