c++ 类成员的初始化顺序

 1 class TestClass1
 2 {
 3 public:
 4     TestClass1()
 5     {
 6         cout << "TestClass1()" << endl;
 7     }
 8     TestClass1(const TestClass1&)
 9     {
10         cout << "TestClass1(const TestClass1&)" << endl;
11     }
12     TestClass1(int i)
13     {
14         cout << "TestClass1(int i) " << i << " " <<endl;
15     }
16 };
17
18 class TestClass2
19 {
20 public:
21     TestClass2() { cout << "TestClass2()" << endl; }
22     TestClass2(const TestClass2&){ cout << "TestClass2(const TestClass2&)" << endl; }
23     int fun() { return 2; }
24 };
25
26 class TestClass3
27 {
28 public:
29     TestClass3(TestClass2& tc2):m_tc2(tc2),m_tc1(m_tc2.fun()) {};
30 private:
31     TestClass1 m_tc1;
32     TestClass2 m_tc2;
33 };
34
35 int main()
36 {
37     TestClass2 tc2;
38     cout << "................................................\n";
39     TestClass3 tc3(tc2);
40     return 0;
41 }

结果：

明明TestClass1的初始化依赖TestClass2，为何TestClass1先于TestClass2初始化。

原文地址：https://www.cnblogs.com/XiaoXiaoShuai-/p/11625390.html