剑指offer-包含min函数的栈-栈和队列-python

题目描述

定义栈的数据结构，请在该类型中实现一个能够得到栈中所含最小元素的min函数（时间复杂度应为O（1））。

# -*- coding:utf-8 -*-
class Solution:
    def __init__(self):
        self.stack = []
        self.minstack = []
    def push(self, node):
        # write code here
        if not self.minstack or self.minstack[-1] >= node:
            self.minstack.append(node)
        self.stack.append(node)
    def pop(self):
        # write code here
        if self.stack[-1]  == self.minstack[-1]:
            self.minstack.pop()
        self.stack.pop()
    def top(self):
        # write code here
        return self.stack[-1]
    def min(self):
        # write code here
        return self.minstack[-1]

原文地址：https://www.cnblogs.com/ansang/p/11993965.html