--各种字符串分拆处理函数.sql
--
--各种字符串分函数
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
Go
--3.2.1 循环截取法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
DECLARE @splitlen int
SET @splitlen=LEN(@split+‘a‘)-2
WHILE CHARINDEX(@split,@s)>0
BEGIN
INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
SET @s=STUFF(@s,1,CHARINDEX(@split,@s)[email protected],‘‘)
END
INSERT @re VALUES(@s)
RETURN
END
GO
/*==============================================*/
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO
--3.2.3.1 使用临时性分拆辅助表法
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
--创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b
INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@[email protected],ID)-ID)
FROM @t
WHERE ID<=LEN(@s+‘a‘)
AND CHARINDEX(@split,@[email protected],ID)=ID
RETURN
END
GO
/*==============================================*/
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[tb_splitSTR]‘) and objectproperty(id,N‘IsUserTable‘)=1)
drop table [dbo].[tb_splitSTR]
GO
--3.2.3.2 使用永久性分拆辅助表法
--字符串分拆辅助表
SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR
FROM syscolumns a,syscolumns b
GO
--字符串分拆处理函数
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS TABLE
AS
RETURN(
SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@[email protected],ID)-ID) as varchar(100))
FROM tb_splitSTR
WHERE ID<=LEN(@s+‘a‘)
AND CHARINDEX(@split,@[email protected],ID)=ID)
GO
/*==============================================*/
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO
--3.2.5 将数据项按数字与非数字再次拆份
CREATE FUNCTION f_splitSTR(
@s varchar(8000), --待分拆的字符串
@split varchar(10) --数据分隔符
)RETURNS @re TABLE(No varchar(100),Value varchar(20))
AS
BEGIN
--创建分拆处理的辅助表(用户定义函数中只能操作表变量)
DECLARE @t TABLE(ID int IDENTITY,b bit)
INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b
INSERT @re
SELECT No=REVERSE(STUFF(col,1,PATINDEX(‘%[^-^.^0-9]%‘,col+‘a‘)-1,‘‘)),
Value=REVERSE(LEFT(col,PATINDEX(‘%[^-^.^0-9]%‘,col+‘a‘)-1))
FROM(
SELECT col=REVERSE(SUBSTRING(@s,ID,CHARINDEX(@split,@[email protected],ID)-ID))
FROM @t
WHERE ID<=LEN(@s+‘a‘)
AND CHARINDEX(@split,@[email protected],ID)=ID)a
RETURN
END
GO
/*==============================================*/
if exists (select * from dbo.sysobjects where id = object_id(N‘[dbo].[f_splitSTR]‘) and xtype in (N‘FN‘, N‘IF‘, N‘TF‘))
drop function [dbo].[f_splitSTR]
GO
--3.2.6 分拆短信数据
CREATE FUNCTION f_splitSTR(@s varchar(8000))
RETURNS @re TABLE(split varchar(10),value varchar(100))
AS
BEGIN
DECLARE @splits TABLE(split varchar(10),splitlen as LEN(split))
INSERT @splits(split)
SELECT ‘AC‘ UNION ALL
SELECT ‘BC‘ UNION ALL
SELECT ‘CC‘ UNION ALL
SELECT ‘DC‘
DECLARE @pos1 int,@pos2 int,@split varchar(10),@splitlen int
SELECT TOP 1
@pos1=1,@split=split,@splitlen=splitlen
FROM @splits
WHERE @s LIKE split+‘%‘
WHILE @pos1>0
BEGIN
SELECT TOP 1
@pos2=CHARINDEX(split,@s,@splitlen+1)
FROM @splits
WHERE CHARINDEX(split,@s,@splitlen+1)>0
ORDER BY CHARINDEX(split,@s,@splitlen+1)
IF @@ROWCOUNT=0
BEGIN
INSERT @re VALUES(@split,STUFF(@s,1,@splitlen,‘‘))
RETURN
END
ELSE
BEGIN
INSERT @re VALUES(@split,SUBSTRING(@s,@splitlen+1,@[email protected]))
SELECT TOP 1
@pos1=1,@split=split,@splitlen=splitlen,@s=STUFF(@s,1,@pos2-1,‘‘)
FROM @splits
WHERE STUFF(@s,1,@pos2-1,‘‘) LIKE split+‘%‘
END
END
RETURN
END
GO
/*
标题：分解字符串并查询相关数据
作者：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开)
时间：2008-03-18
地点：广东深圳
说明：通过使用函数等方法分解字符串查询相关数据。
问题：通过分解一个带某种符号分隔的字符串在数据库中查找相关数据。
例如 @str = ‘1,2,3‘,查询下表得到记录1,4,5,6
ID TypeID
1 1,2,3,4,5,6,7,8,9,10,11,12
2 2,3
3 3,7,8,9
4 2,6
5 4,5
6 6,7
*/
-----------------------------
create table tb (ID int , TypeID varchar(30))
insert into tb values(1 , ‘1,2,3,4,5,6,7,8,9,10,11,12‘)
insert into tb values(2 , ‘2,3‘)
insert into tb values(3 , ‘3,7,8,9‘)
insert into tb values(4 , ‘2,6‘)
insert into tb values(5 , ‘4,5‘)
insert into tb values(6 , ‘6,7‘)
go
-----------------------------
--如果仅仅是一个,如@str = ‘1‘.
declare @str as varchar(30)
set @str = ‘1‘
select * from tb where charindex(‘,‘ + @str + ‘,‘ , ‘,‘ + TypeID + ‘,‘) > 0
select * from tb where ‘,‘ + TypeID + ‘,‘ like ‘%,‘ + @str + ‘,%‘
/*
ID TypeID
----------- ------------------------------
1 1,2,3,4,5,6,7,8,9,10,11,12
（所影响的行数为 1 行）
*/
-----------------------------
--如果包含两个,如@str = ‘1,2‘.
declare @str as varchar(30)
set @str = ‘1,2‘
select * from tb where charindex(‘,‘ + left(@str , charindex(‘,‘ , @str) - 1) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0 or
charindex(‘,‘ + substring(@str , charindex(‘,‘ , @str) + 1 , len(@str)) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0
select * from tb where ‘,‘ + typeid + ‘,‘ like ‘%,‘ + left(@str , charindex(‘,‘ , @str) - 1) + ‘,%‘ or
‘,‘ + typeid + ‘,‘ like ‘%,‘ + substring(@str , charindex(‘,‘ , @str) + 1 , len(@str)) + ‘,%‘
/*
ID TypeID
----------- ------------------------------
1 1,2,3,4,5,6,7,8,9,10,11,12
2 2,3
4 2,6
（所影响的行数为 3 行）
*/
-------------------------------------------
--如果包含三个或四个，用PARSENAME函数来处理.
declare @str as varchar(30)
set @str = ‘1,2,3,4‘
select * from tb where
charindex(‘,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 4) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0 or
charindex(‘,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 3) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0 or
charindex(‘,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 2) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0 or
charindex(‘,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 1) + ‘,‘ , ‘,‘ + typeid + ‘,‘) > 0
select * from tb where
‘,‘ + typeid + ‘,‘ like ‘%,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 4) + ‘,%‘ or
‘,‘ + typeid + ‘,‘ like ‘%,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 3) + ‘,%‘ or
‘,‘ + typeid + ‘,‘ like ‘%,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 2) + ‘,%‘ or
‘,‘ + typeid + ‘,‘ like ‘%,‘ + parsename(replace(@str , ‘,‘ , ‘.‘) , 1) + ‘,%‘
/*
ID TypeID
----------- ------------------------------
1 1,2,3,4,5,6,7,8,9,10,11,12
2 2,3
3 3,7,8,9
4 2,6
5 4,5
（所影响的行数为 5 行）
*/
---------------------------------------
--如果超过四个，则只能使用函数或动态SQL来分解并查询数据。
/*
名称：fn_split函数.
功能：实现字符串分隔功能的函数
*/
create function dbo.fn_split(@inputstr varchar(8000), @seprator varchar(10))
returns @temp table (a varchar(200))
as
begin
declare @i int
set @inputstr = rtrim(ltrim(@inputstr))
set @i = charindex(@seprator , @inputstr)
while @i >= 1
begin
insert @temp values(left(@inputstr , @i - 1))
set @inputstr = substring(@inputstr , @i + 1 , len(@inputstr) - @i)
set @i = charindex(@seprator , @inputstr)
end
if @inputstr <> ‘/‘
insert @temp values(@inputstr)
return
end
go
--调用
declare @str as varchar(30)
set @str = ‘1,2,3,4,5‘
select distinct m.* from tb m,
(select * from dbo.fn_split(@str,‘,‘)) n
where charindex(‘,‘ + n.a + ‘,‘ , ‘,‘ + m.typeid + ‘,‘) > 0
drop table tb
drop function dbo.fn_split
/*
ID TypeID
----------- ------------------------------
1 1,2,3,4,5,6,7,8,9,10,11,12
2 2,3
3 3,7,8,9
4 2,6
5 4,5
（所影响的行数为 5 行）
*/
------------------------------------------
--使用动态SQL的语句。
declare @str varchar(200)
declare @sql as varchar(1000)
set @str = ‘1,2,3,4,5‘
set @sql = ‘select ‘‘‘ + replace(@str , ‘,‘ , ‘‘‘ as id union all select ‘‘‘)
set @sql = @sql + ‘‘‘‘
set @sql = ‘select distinct a.* from tb a , (‘ + @sql + ‘) b where charindex(‘ + ‘‘‘,‘‘ + b.id + ‘ + ‘‘‘,‘‘‘ + ‘ , ‘ + ‘‘‘,‘‘ + a.typeid + ‘ + ‘‘‘,‘‘‘ + ‘) > 0 ‘
exec (@sql)
/*
ID TypeID
----------- ------------------------------
1 1,2,3,4,5,6,7,8,9,10,11,12
2 2,3
3 3,7,8,9
4 2,6
5 4,5
（所影响的行数为 5 行）
*/
---分拆列值
--原著：邹建
--改编：爱新觉罗.毓华(十八年风雨,守得冰山雪莲花开) 2007-12-16 广东深圳
--有表tb, 如下:
id value
----------- --------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
1. 旧的解决方法(sql server 2000)
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b
SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(‘,‘, A.[values] + ‘,‘, B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(‘,‘ + A.[values], B.id, 1) = ‘,‘
DROP TABLE #
2. 新的解决方法(sql server 2005)
create table tb(id int,value varchar(30))
insert into tb values(1,‘aa,bb‘)
insert into tb values(2,‘aaa,bbb,ccc‘)
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,‘ <root> <v>‘ + REPLACE([value], ‘,‘, ‘ </v> <v>‘) + ‘ </v> </root>‘) FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value(‘.‘, ‘varchar(100)‘) FROM A.[value].nodes(‘/root/v‘) N(v)
)B
DROP TABLE tb
/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc
(5 行受影响)
*/