Java for LeetCode 058 Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

解题思路:

从后往前遍历,用一个指针rightIndex表示第一次出现飞空格的位置,然后继续遍历,找出第一次出现空格的位置即可,JAVA实现如下:

   static public int lengthOfLastWord(String s) {
	   	int rightIndex=s.length()-1;
	   	while(rightIndex>=0&&s.charAt(rightIndex)==‘ ‘)
	   		rightIndex--;
	   	if(rightIndex<0)
	   		return 0;
        for(int i=rightIndex-1;i>=0;i--)
        	if(s.charAt(i)==‘ ‘)
        		return rightIndex-i;
        return rightIndex+1;
    }
时间: 2024-12-16 19:32:32

Java for LeetCode 058 Length of Last Word的相关文章

【Leetcode】Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha

leetcode 题解: Length of Last Word

leetcode: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non

【LeetCode】- Length of Last Word(最后一个单词的长度)

[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.如果这个单词不存在,则返回0. [ 分析 : ] A word is defined

Java [Leetcode 58]Length of Last Word

题目描述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa

leetcode 58 Length of Last Word ----- java

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha

Java for LeetCode 211 Add and Search Word - Data structure design

Design a data structure that supports the following two operations: void addWord(word)bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter.

[LeetCode][JavaScript]Length of Last Word

Length of Last Word Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consi

[LeetCode] 58. Length of Last Word 求末尾单词的长度

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha

leetCode 58. Length of Last Word 字符串

58. Length of Last Word Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence c