LeetCode: Length of Last Word [057]

昨天同事在做主从时，从库报如下错误：

Got fatal error 1236 from master when reading data from binary log: ‘Misconfigured master - server id was not set‘

粗粗看好像是master的server-id没有设置，但同事做如下查询：

备库采集：
[email protected] Fri May 23 14:18:59 2014 14:18:59 [(none)]> show variables like ‘%server_id%‘;
+---------------+-------+
| Variable_name | Value |
+---------------+-------+
| server_id     | 2     |
+---------------+-------+

主库采集：

mysql> show variables like ‘%server%‘;
+----------------------+-------------------+
| Variable_name        | Value             |
+----------------------+-------------------+
| character_set_server | latin1            |
| collation_server     | latin1_swedish_ci |
| server_id            | 1                 |
+----------------------+-------------------+

此时，复制环境的server-id确实是全局唯一的。为何报错？

由于业务是用于存储hadoop的元数据，之前MySQL版本较低，同事用了比master版本高的slave，本以为是这个原因，但在MySQL 的bug列表上发现：

该发现否定了我们之前的判断，经过同事那边的测试，也确实是这个bug :-)

祝周末愉快，

Good Luck！

LeetCode: Length of Last Word [057]

时间： 2024-08-15 22:38:18

LeetCode: Length of Last Word [057]的相关文章

LeetCode——Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha

LeetCode Length of Last Word

1. 题目 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa

[LeetCode] Length of Last Word 字符串查找

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha

leetcode : Length of Last Word [基本功]

p.p1 { margin: 0.0px 0.0px 0.0px 0.0px; font: 14.0px "Helvetica Neue"; color: #333333 } p.p2 { margin: 0.0px 0.0px 0.0px 0.0px; font: 14.0px "Helvetica Neue"; color: #333333; background-color: #ffffff } p.p3 { margin: 0.0px 0.0px 0.0px

[Leetcode] Length of last word 最后一个单词的长度

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space char

Leetcode: Length of Last Word in python

Length of Last Word Total Accepted: 47690 Total Submissions: 168587 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note:

leetcode Length of Last Word(easy) /java

坑主要在处理空格.因为字符串之间不止有一个空格. import java.io.*; import java.util.*; public class Solution { public static int lengthOfLastWord(String s) { int r=0; int len=s.length(); if(len==0) return 0; int i,j; char[] c=s.toCharArray(); int flag=1; for(i=0;i<len;i++)

LeetCode Length of Last Word 最后一个字的长度

1 class Solution { 2 public: 3 int lengthOfLastWord(const char *s) { 4 if(s=="") return 0; 5 string snew=s; 6 int n=0,len=strlen(s); 7 char *p=&snew[len-1]; 8 while(*p==' '&&len!=0){ 9 *p--; 10 len--; 11 } 12 while(*p!=' '&&l

【Leetcode】Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha