Leetcode 617.合并二叉树

合并二叉树

给定两个二叉树,想象当你将它们中的一个覆盖到另一个上时,两个二叉树的一些节点便会重叠。

你需要将他们合并为一个新的二叉树。合并的规则是如果两个节点重叠,那么将他们的值相加作为节点合并后的新值,否则不为 NULL 的节点将直接作为新二叉树的节点。

示例 1:

输入:

输出:

合并后的树:

注意: 合并必须从两个树的根节点开始。

 1 /**
 2  * Definition for a binary tree node.
 3  * public class TreeNode {
 4  *     int val;
 5  *     TreeNode left;
 6  *     TreeNode right;
 7  *     TreeNode(int x) { val = x; }
 8  * }
 9  */
10 class Solution {
11     public TreeNode mergeTrees(TreeNode t1, TreeNode t2) {
12         if(t1!=null&&t2!=null) t1.val=t1.val+t2.val;
13         if(t1==null&&t2!=null){
14             t1=new TreeNode(t2.val);
15         }
16         if(t2!=null){
17             t1.left=mergeTrees(t1.left,t2.left);
18             t1.right=mergeTrees(t1.right,t2.right);
19         }
20         return t1;
21     }
22 }

原文地址:https://www.cnblogs.com/kexinxin/p/10381427.html

时间: 2024-07-31 15:22:15

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