二分加最短路
#include <stdio.h> #include <string.h> #define N 1005 #define INF 0x3f3f3f3f struct tt{ int h,cost; }dis[N][N]; int vis[N],d[N],num =1; int dijkstral(int v0,int t,int n,int h) { int i,temp,x,y; for(i = 1 ; i <= n ; i++) { if(dis[v0][i].h>=h){ d[i] = dis[v0][i].cost; }else d[i] = INF; vis[i] = 0; } d[v0] = 0; vis[v0] = 1; for(i = 1 ; i <= n ; i++) { temp = INF ; for(y = 1 ; y <= n ; y++) if(!vis[y] && temp>d[y]) temp = d[x=y]; if(temp == INF) return 0; vis[x] = 1; if(x == t) return 1; for(y = 1 ; y <= n ; y++) if(!vis[y] &&dis[x][y].cost+d[x]<d[y]&&dis[x][y].h>=h) d[y] = d[x] + dis[x][y].cost; } return 0; } int main() { int R,C,s,t,h_limit,i,j,cas = 1; while(~scanf("%d %d",&C,&R),C+R) { for(i = 1 ; i <= C ; i++) { for(j = 1 ; j <= C ; j++) { dis[i][j].cost = (i == j) ?0:INF; dis[i][j].h = 0; } } while(R--) { int x,y,h,val; scanf("%d %d %d %d",&x,&y,&h,&val); if(h == -1) h = INF; dis[x][y].cost = dis[y][x].cost = val; dis[x][y].h = dis[y][x].h = h; } scanf("%d %d %d",&s,&t,&h_limit); int l = 1 ,r = h_limit,mid,ans; while(l<=r) { mid = l+(r-l)/2; if(dijkstral(s,t,C,mid)){ ans = d[t]; l = mid+1; }else r = mid-1; } if(cas>1) printf("\n"); printf("Case %d:\n",cas++); if(r<=0) printf("cannot reach destination\n"); else { printf("maximum height = %d\n",r); printf("length of shortest route = %d\n",ans); } } return 0; }
hdu 2962
时间: 2024-10-14 04:55:14