实现退出方式要activity的 boolean onKeyDown(int keyCode, KeyEvent event) 方法里实现
直接见代码吧:
方法一:
@Override public boolean onKeyDown(int keyCode, KeyEvent event) { //退出方法一 if(keyCode == KeyEvent.KEYCODE_BACK){ AlertDialog.Builder dialog = new AlertDialog.Builder(this); dialog.setTitle("提示"); dialog.setMessage("确定要残忍地退出应用?"); dialog.setPositiveButton("确定",new DialogInterface.OnClickListener(){ @Override public void onClick(DialogInterface dialog, int which) { finish(); } }); dialog.setNegativeButton("取消",new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { return ; } }); dialog.show(); } return super.onKeyDown(keyCode, event); }
方法二:
private long existTime = 0; @Override public boolean onKeyDown(int keyCode, KeyEvent event) { //退出方法二 if(keyCode == KeyEvent.KEYCODE_BACK && event.getAction() == KeyEvent.ACTION_DOWN){ if(System.currentTimeMillis()-existTime > 2000){ Toast.makeText(this,"再按一次退出应用",Toast.LENGTH_SHORT).show(); existTime = System.currentTimeMillis(); }else { finish(); } return true; //退出 } return super.onKeyDown(keyCode, event); }
时间: 2024-10-10 14:56:07