等比数列求和公式

http://acm.hit.edu.cn/hoj/problem/view?id=3152 Dice My Tags (Edit) Source : Time limit : 1 sec Memory limit : 128 M Submitted : 82, Accepted : 18 You have a dice with M faces, each face contains a distinct number. Your task is to calculate the expect

题目传送门:B-Icebound and Sequence(19年河北省赛) 题目大意: 等比数列求和,结果取模 分析: 因为取模操作,直接运用等比数列求和公式无法做出,所以需要用到公式 求等比为k的等比数列之和S[n]..当n为偶数..S[n] = S[n/2] + pow(k,n/2) * S[n/2] n为奇数...S[n] = S[n/2] + pow(k,n/2) * S[n/2] + pow(k,n)等比数列第n个数的值 代码: #include<bits/stdc++.h> us

问题描述: 样例: 实现解释: 这里等比数列求和使用到的知识点包括:分治和快速幂 其中分治的方法和快速幂的方法是从博客中学习到的: 等比数列分治求和:https://blog.csdn.net/qq_35937273/article/details/82750298 快速幂方法:https://www.cnblogs.com/lca1826/p/6748372.html 结合到本题目中可参考完整代码. 在分治求和和快速幂之外取模操作的实现解释如下: 根据描述可知最后的值是很大的,所以需要取余,但

Poor Akagi Time Limit: 30000/15000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 131    Accepted Submission(s): 29 Problem Description Akagi is not only good at basketball but also good at math. Recently, he got a

题目传送:http://acm.hdu.edu.cn/showproblem.php?pid=4704 Problem Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input file consists of multiple test cases. 题意是输入一个N,求N被分成1个数的结果+被分成2个数的结果+...+被分成N个数的结果,N很大 1.隔板原理 1~N有

#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> using namespace std; typedef long long ll; ll n,p; ll k; #define N 4000000 ll a[N],fr[N]; struct sq{ ll a[3][3]; sq(){memset(a,0,sizeof(a));} sq operator*(sq

[Tjoi2016&Heoi2016]求和 Time Limit: 40 Sec  Memory Limit: 128 MBSubmit: 679  Solved: 534[Submit][Status][Discuss] Description 在2016年,佳媛姐姐刚刚学习了第二类斯特林数,非常开心. 现在他想计算这样一个函数的值: S(i, j)表示第二类斯特林数,递推公式为: S(i, j) = j ∗ S(i − 1, j) + S(i − 1, j − 1), 1 <= j &l

题解:http://bestcoder.hdu.edu.cn/blog/ 1 多校6 1001 HDU5793 A Boring Question 2 3 4 // #pragma comment(linker, "/STACK:102c000000,102c000000") 5 // #include <conio.h> 6 #include <bits/stdc++.h> 7 using namespace std; 8 #define clc(a,b) m

Sumdiv Sumdiv Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15364   Accepted: 3790 Description Consider two natural numbers A and B. Let S be the sum of all natural divisors of A^B. Determine S modulo 9901 (the rest of the division of