Log格式化输出JSON内容

以前常做的一件事就是把返回的json复制到格式化工具里看内容，Json格式化方法那么多直接格式化LOG不是很省事。

很早前写的简单LOG类（Log.java）

import android.text.TextUtils;

/**
 * 日志信息
 *
 * @author Harlan Song
 * @createDate 2013-2-8
 */
public class Log {

    /**
     * 日志开关
     */
    private static boolean isDebug = true;

    private static final String AUTHOR ="HARLAN -->";

    public static void debug(boolean status){
        isDebug = status;
    }

    public static void d(String tag, String message) {
        if (isDebug) {
            android.util.Log.d(tag,AUTHOR + message);
        }
    }

    public static void i(String tag, String message) {
        if (isDebug) {
            android.util.Log.i(tag, AUTHOR +message);
        }
    }

    /**
     * Json格式化输出
     * @param tag
     * @param message 内容
     * @param isOutputOriginalContent 是否输入原内容
     */
    public static void iJsonFormat(String tag, String message,boolean isOutputOriginalContent) {
        if (isDebug && !TextUtils.isEmpty(message)) {
            if(isOutputOriginalContent)
                android.util.Log.i(tag, AUTHOR + message);
            android.util.Log.i(tag, AUTHOR +"\n" + JsonUtils.format(StringUtils.convertUnicode(message)));
        }
    }

    public static void w(String tag, String message) {
        if (isDebug) {
            android.util.Log.w(tag,AUTHOR + message);
        }

    }

    public static void e(String tag, String message) {
        if (isDebug) {
            android.util.Log.e(tag,AUTHOR + message);
        }
    }
}

调用iJsonFormat就可以了，先把内容Unicode转换再格式化JSON，不然如果显示的是unicode后的内容中文看不出来也不方便.

Unicode解码方法，网上很多了。

 public static String convertUnicode(String ori) {
        char aChar;
        int len = ori.length();
        StringBuffer outBuffer = new StringBuffer(len);
        for (int x = 0; x < len; ) {
            aChar = ori.charAt(x++);
            if (aChar == ‘\\‘) {
                aChar = ori.charAt(x++);
                if (aChar == ‘u‘) {
                    // Read the xxxx
                    int value = 0;
                    for (int i = 0; i < 4; i++) {
                        aChar = ori.charAt(x++);
                        switch (aChar) {
                            case ‘0‘:
                            case ‘1‘:
                            case ‘2‘:
                            case ‘3‘:
                            case ‘4‘:
                            case ‘5‘:
                            case ‘6‘:
                            case ‘7‘:
                            case ‘8‘:
                            case ‘9‘:
                                value = (value << 4) + aChar - ‘0‘;
                                break;
                            case ‘a‘:
                            case ‘b‘:
                            case ‘c‘:
                            case ‘d‘:
                            case ‘e‘:
                            case ‘f‘:
                                value = (value << 4) + 10 + aChar - ‘a‘;
                                break;
                            case ‘A‘:
                            case ‘B‘:
                            case ‘C‘:
                            case ‘D‘:
                            case ‘E‘:
                            case ‘F‘:
                                value = (value << 4) + 10 + aChar - ‘A‘;
                                break;
                            default:
                                throw new IllegalArgumentException(
                                        "Malformed   \\uxxxx   encoding.");
                        }
                    }
                    outBuffer.append((char) value);
                } else {
                    if (aChar == ‘t‘)
                        aChar = ‘\t‘;
                    else if (aChar == ‘r‘)
                        aChar = ‘\r‘;
                    else if (aChar == ‘n‘)
                        aChar = ‘\n‘;
                    else if (aChar == ‘f‘)
                        aChar = ‘\f‘;
                    outBuffer.append(aChar);
                }
            } else
                outBuffer.append(aChar);

        }
        return outBuffer.toString();
    }

JSON格式化方法，同样是网上找的。

 public static String format(String jsonStr) {
        int level = 0;
        StringBuffer jsonForMatStr = new StringBuffer();
        for(int i=0;i<jsonStr.length();i++){
            char c = jsonStr.charAt(i);
            if(level>0&&‘\n‘==jsonForMatStr.charAt(jsonForMatStr.length()-1)){
                jsonForMatStr.append(getLevelStr(level));
            }
            switch (c) {
                case ‘{‘:
                case ‘[‘:
                    jsonForMatStr.append(c+"\n");
                    level++;
                    break;
                case ‘,‘:
                    jsonForMatStr.append(c+"\n");
                    break;
                case ‘}‘:
                case ‘]‘:
                    jsonForMatStr.append("\n");
                    level--;
                    jsonForMatStr.append(getLevelStr(level));
                    jsonForMatStr.append(c);
                    break;
                default:
                    jsonForMatStr.append(c);
                    break;
            }
        }

        return jsonForMatStr.toString();

    }

    private static String getLevelStr(int level){
        StringBuffer levelStr = new StringBuffer();
        for(int levelI = 0;levelI<level ; levelI++){
            levelStr.append("\t");
        }
        return levelStr.toString();
    }

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