Java实现根据经纬度计算距离

在项目开发过程中，需要根据两地经纬度坐标计算两地间距离，所用的工具类如下:

Demo1:

public static double getDistatce(double lat1, double lat2, double lon1, double lon2) {
        double R = 6371;
        double distance = 0.0;
        double dLat = (lat2 - lat1) * Math.PI / 180;
        double dLon = (lon2 - lon1) * Math.PI / 180;
        double a = Math.sin(dLat / 2) * Math.sin(dLat / 2)
                + Math.cos(lat1 * Math.PI / 180)
                * Math.cos(lat2 * Math.PI / 180) * Math.sin(dLon / 2)
                * Math.sin(dLon / 2);
        distance = (2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a))) * R;
        return distance;
    }

Demo2:

private static final double EARTH_RADIUS = 6378.137 * 1000;
    private static double rad(double d)
    {
       return d * Math.PI / 180.0;
    }
    public static double GetDistance(double lat1, double lng1, double lat2, double lng2)
    {
       double radLat1 = rad(lat1);
       double radLat2 = rad(lat2);
       double a = radLat1 - radLat2;
       double b = rad(lng1) - rad(lng2);
       double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2) +
        Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));
       s = s * EARTH_RADIUS ;
       s = Math.round(s * 10000) / 10000;
       return s;
    } 

Demo3:

private static final double EARTH_RADIUS = 6378137;//赤道半径(单位m)  

    /**
     * 转化为弧度(rad)
     * */
    private static double rad(double d)
    {
       return d * Math.PI / 180.0;
    }  

    /**
     * 基于余弦定理求两经纬度距离
     * @param lon1 第一点的精度
     * @param lat1 第一点的纬度
     * @param lon2 第二点的精度
     * @param lat3 第二点的纬度
     * @return 返回的距离，单位km
     * */
    public static double LantitudeLongitudeDist(double lon1, double lat1,double lon2, double lat2) {
        double radLat1 = rad(lat1);
        double radLat2 = rad(lat2);  

        double radLon1 = rad(lon1);
        double radLon2 = rad(lon2);  

        if (radLat1 < 0)
            radLat1 = Math.PI / 2 + Math.abs(radLat1);// south
        if (radLat1 > 0)
            radLat1 = Math.PI / 2 - Math.abs(radLat1);// north
        if (radLon1 < 0)
            radLon1 = Math.PI * 2 - Math.abs(radLon1);// west
        if (radLat2 < 0)
            radLat2 = Math.PI / 2 + Math.abs(radLat2);// south
        if (radLat2 > 0)
            radLat2 = Math.PI / 2 - Math.abs(radLat2);// north
        if (radLon2 < 0)
            radLon2 = Math.PI * 2 - Math.abs(radLon2);// west
        double x1 = EARTH_RADIUS * Math.cos(radLon1) * Math.sin(radLat1);
        double y1 = EARTH_RADIUS * Math.sin(radLon1) * Math.sin(radLat1);
        double z1 = EARTH_RADIUS * Math.cos(radLat1);  

        double x2 = EARTH_RADIUS * Math.cos(radLon2) * Math.sin(radLat2);
        double y2 = EARTH_RADIUS * Math.sin(radLon2) * Math.sin(radLat2);
        double z2 = EARTH_RADIUS * Math.cos(radLat2);  

        double d = Math.sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)+ (z1 - z2) * (z1 - z2));
        //余弦定理求夹角
        double theta = Math.acos((EARTH_RADIUS * EARTH_RADIUS + EARTH_RADIUS * EARTH_RADIUS - d * d) / (2 * EARTH_RADIUS * EARTH_RADIUS));
        double dist = theta * EARTH_RADIUS;
        return dist;
    }

Demo4:

//google map
private static final  double EARTH_RADIUS = 6378137;//赤道半径(单位m)  

    /**
     * 转化为弧度(rad)
     * */
    private static double rad(double d)
    {
       return d * Math.PI / 180.0;
    }
    /**
     * 基于googleMap中的算法得到两经纬度之间的距离,计算精度与谷歌地图的距离精度差不多，相差范围在0.2米以下
     * @param lon1 第一点的精度
     * @param lat1 第一点的纬度
     * @param lon2 第二点的精度
     * @param lat3 第二点的纬度
     * @return 返回的距离，单位km
     * */
    public static double GetDistance(double lon1,double lat1,double lon2, double lat2)
    {
       double radLat1 = rad(lat1);
       double radLat2 = rad(lat2);
       double a = radLat1 - radLat2;
       double b = rad(lon1) - rad(lon2);
       double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a/2),2)+Math.cos(radLat1)*Math.cos(radLat2)*Math.pow(Math.sin(b/2),2)));
       s = s * EARTH_RADIUS;
       s = Math.round(s * 10000) / 10000;
       return s;
    }

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原文地址：https://www.cnblogs.com/shaoye007/p/10196530.html