推送消息，程序正在运行的时候弹出弹框问题解决

在这个方法里面处理获取的远程推送消息

- (void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo fetchCompletionHandler:(void (^)(UIBackgroundFetchResult))completionHandler

{

// 取得 APNs 标准信息内容

NSDictionary *aps = [userInfo valueForKey:@"aps"];

NSString *content = [aps valueForKey:@"alert"]; //推送显示的内容

if (content.length != 0) {

if ([userInfo valueForKey:@"webUrl"])

{

webUrl = [userInfo valueForKey:@"webUrl"];

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:nil

message:content

delegate:self

cancelButtonTitle:@"取消"

otherButtonTitles: @"去看看",nil];

alert.tag = 10000;

[alert show];

}

else

{

UIAlertView *alert = [[UIAlertView alloc] initWithTitle:nil

message:content

delegate:nil

cancelButtonTitle:@"知道了"

otherButtonTitles: nil];

[alert show];

}

}

}

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