LeetCode——Valid Sudoku

Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘.

A partially filled sudoku which is valid.

Note:

A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

原题链接：https://oj.leetcode.com/problems/valid-sudoku/

按照数独的规则，一行、一列、对角线、9个小格中不出现同一个数字。

import java.util.ArrayList;
import java.util.List;

public class ValidSudoku {
	public boolean isValidSudoku(char[][] board) {
		for(int i=0;i<9;i++){
			List<Character> list = new ArrayList<Character>();
			for(int j=0;j<9;j++)
				list.add(board[i][j]);
			if(!isValid(list))
				return false;
		}
		for(int i=0;i<9;i++){
			List<Character> list = new ArrayList<Character>();
			for(int j=0;j<9;j++)
				list.add(board[j][i]);
			if(!isValid(list))
				return false;
		}
		for(int i=0;i<3;i++){
			for(int j=0;j<3;j++){
				List<Character> list = new ArrayList<Character>();
				for(int k=0;k<3;k++){
					for(int l=0;l<3;l++){
						list.add(board[i*3+k][j*3+l]);
					}
				}
				if(!isValid(list))
					return false;
			}
		}
		return true;
	}
	private boolean isValid(List<Character> list){
		for(Character ch : list){
			if(ch != '.')
				if(list.indexOf(ch) != list.lastIndexOf(ch))
					return false;
		}
		return true;
	}
}