两种思路吧,递归 和 非递归
递归
$arr = [ 1=>[‘id‘=>1,‘pid‘=>0], 2=>[‘id‘=>2,‘pid‘=>0], 3=>[‘id‘=>3,‘pid‘=>1], 4=>[‘id‘=>4,‘pid‘=>1], 5=>[‘id‘=>5,‘pid‘=>0], 6=>[‘id‘=>6,‘pid‘=>3], 7=>[‘id‘=>7,‘pid‘=>6], 8=>[‘id‘=>8,‘pid‘=>3], 9=>[‘id‘=>9,‘pid‘=>4], 10=>[‘id‘=>10,‘pid‘=>7], 11=>[‘id‘=>11,‘pid‘=>7], ]; //排序数组arr 层数level 键val function display_test($arr,$level,$val){ if($level==0) { echo "顶级目录\n"; }else{ echo str_repeat(‘ ‘,$level).$arr[$val][‘id‘]."\n"; } $temp = get($arr,$val); foreach ($temp as $v) { display_test($arr,$level+1,$v[‘id‘]); } } //获取 pid的所有下一级子节点 function get($arr,$pid) { $res = []; foreach ($arr as $v) { if($v[‘pid‘]==$pid) { $res[] = $v; } } return $res; } display_test($arr,0,0);die;
非递归 左右值法
表结构
CREATE TABLE `sys_department` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(20) DEFAULT NULL COMMENT ‘部门名称‘, `description` varchar(200) DEFAULT NULL COMMENT ‘描述‘, `create_time` int(11) DEFAULT NULL COMMENT ‘添加时间‘, `left_value` int(11) DEFAULT NULL, `right_value` int(11) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8 COMMENT=‘部门表‘
添加新下级:用事物
//修改右值 $sql = "UPDATE {$this->table} SET right_value = right_value+2 WHERE right_value>=:right_value"; //修改左值 $sql = "UPDATE {$this->table} SET left_value = left_value+2 WHERE left_value>=:left_value"; //插入 $sql = "INSERT INTO {$this->table}(name,description,left_value,right_value,create_time) VALUES(:name,:description,:left_value,:right_value,:create_time)";
删除节点: 用事物
//删除 $sql = "DELETE FROM {$this->table} WHERE left_value>=:left_value AND right_value<=:right_value"; //修改左值 $sql = "UPDATE {$this->table} SET left_value=left_value-{$offset} WHERE left_value>:left_value"; //修改右值 $sql = "UPDATE {$this->table} SET right_value=right_value-{$offset} WHERE right_value>:right_value";
获取所有节点,包含缩进
public function display_tree($id){ //获取节点 $model = $this->model->getById($id); if(!$model) { return false; } $left = $model[‘left_value‘]; $right = $model[‘right_value‘]; //获取子节点 按left_value排序 $res = $this->getByLeftRight($left,$right); $temp = []; //循环找出节点所在级数 foreach ($res as $k=>$v) { if(count($temp)>0) { // 检查我们是否应该将节点移出堆栈 while ($temp[count($temp) - 1] < $v[‘right_value‘]) { array_pop($temp); } } //echo str_repeat("*",count($temp)).$v[‘name‘]."\n"; $res[$k][‘level‘] = count($temp); $temp[] = $v[‘right_value‘]; } //level 第几层 return $res; }
时间: 2024-10-21 10:14:13