hdu5387Clock

//给出时间，求时针和分针，时针和秒针，分针和秒针的夹角
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std ;
#define abs(a) a < 0 ? -a :a
int s , t , h ;
int gcd(int a , int b)
{
    if(b == 0)return a ;
    return gcd(b , a%b) ;
}
int main()
{
   // freopen("in.txt" , "r" , stdin) ;
    int T ;
    scanf("%d", &T) ;
    while(T--)
    {
        scanf("%d:%d:%d" , &h , &t , &s) ;
        int hd = (3600*h+60*t+s)%43200 ;
        int td = (60*t+s)*12 ;
        int sd = s*6*120 ;
        int ans_1 = abs(((hd - td)));ans_1 = ans_1 > 21600 ? (43200-ans_1) : ans_1 ;
        int ans_2 = abs(((hd -sd))) ;ans_2 = ans_2 > 21600 ? (43200-ans_2) : ans_2 ;
        int ans_3 = abs(((sd - td)));ans_3 = ans_3 > 21600 ? (43200-ans_3) : ans_3 ;
        int g1 = gcd(ans_1 , 120) ;
        if(g1 == 120)
        printf("%d" , ans_1/120) ;
        else
        printf("%d/%d" , ans_1/g1 , 120/g1) ;
        int g2 = gcd(ans_2 , 120) ;
        if(g2 == 120)
        printf(" %d" , ans_2/120) ;
        else
        printf(" %d/%d" , ans_2/g2 , 120/g2) ;
        int g3 = gcd(ans_3 , 120) ;
        if(g3 == 120)
        printf(" %d \n" , ans_3/120) ;
        else
        printf(" %d/%d \n" , ans_3/g3 , 120/g3) ;
    }
}

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