第六场C

题意：B的数据加强版

思路：RMQ

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3
 4 int a[200005];
 5 int d[200005][20];
 6 struct node{
 7     int x,y;
 8 }b[2005];
 9 bool cmp(node p,node q){
10     return p.x<q.x;
11 }
12 int RMQ(int l,int r){
13     int k=0;
14     while((1<<(k+1))<=r-l+1)
15         k++;
16     return min(d[l][k],d[r-(1<<k)+1][k]);
17 }
18 int main(){
19     int n,kk;
20     scanf("%d%d",&n,&kk);
21     memset(d,127,sizeof(d));
22     for(int i=0;i<n;i++){
23         scanf("%d",&a[i]);
24         d[i][0]=a[i];
25     }
26     for(int j=1;(1<<j)<=n;j++)
27     for(int i=0;i+(1<<j)-1<n;i++){
28         d[i][j]=min(d[i][j-1],d[i+(1<<(j-1))][j-1]);
29     }
30     int m;
31     scanf("%d",&m);
32     for(int i=1;i<=m;i++){
33         scanf("%d%d",&b[i].x,&b[i].y);
34     }
35     int xx,yy;
36     int sum;
37     int ssum=0;
38     sort(b+1,b+1+m,cmp);
39     for(int i=1;i<=m;i++){
40         for(int j=i+1;j<=m;j++){
41             sum=0;
42             yy=b[i].y;
43             yy=RMQ(b[i].x,b[j].x-1);
44             sum+=b[j].x-b[i].x;
45             sum+=b[i].y-yy;
46             sum+=abs(yy-b[j].y);
47             if(sum<=kk) ssum++;
48         }
49     }
50
51     cout<<ssum<<endl;
52 }