基于Verilog的汽车尾灯控制器的实现

首先进行模块的定义

模块具有三个输入：时钟，重置，和汽车状态、以及六个输出分别控制左右（l,r）三色LED的红绿蓝三个阴极

   module   ?   car_rear_light
   (???   input   ?clk,
   ????   input   ?rst,
   ????   input   ?[   3   :   0   ]car_status,
   ????   output   ?   reg   [   0   :   0   ]l_light_r,???????   //左侧红灯
   ????   output   ?   reg   [   0   :   0   ]r_light_r,???????   //右侧红灯
   ????   output   ?   reg   [   0   :   0   ]l_light_g,???????   //左侧绿灯
   ????   output   ?   reg   [   0   :   0   ]r_light_g,???????   //右侧绿灯?
   ????   output   ?   reg   [   0   :   0   ]l_light_b,???????   //左侧蓝灯
   ????   output   ?   reg   [   0   :   0   ]r_light_b????????   //右侧蓝灯
   );  

因为左右转向灯和双闪均为黄色，所以将左右两个三色LED的红、绿阴极统一安排给l_light、r_light两个变量控制
红+绿 <= 污黄

   reg   [   0   :   0   ]l_light;
   reg   [   0   :   0   ]r_light;  

   always   @(   posedge   ?clk)
   begin
   ????l_light_r?   =   ?l_light;
   ????l_light_g?   =   ?l_light;
   ????r_light_r?   =   ?r_light;
   ????r_light_g?   =   ?r_light;
   end  

下面进行1Hz的分频

分频模块重新定义参数，分频系数为12M，将板载12MHz的晶振分为1Hz的时钟。

   wire   ?clk_1Hz;  

   divide   ??#(.WIDTH(   32   ),.N(   12_000_000   ))??   u1   ?(??????   //分频12MHz到1Hz
   ????.clk????(clk),
   ????.rst_n??(rst),
   ????.clkout?(clk_1Hz)???
   );  

最后是逻辑部分的描述

汽车状态由拨码开关控制：
0001 —— 直行，不闪灯
0010 —— 左转，闪左灯
0100 —— 右转，闪右灯
1000 —— 故障，双闪
1111 —— 倒车，两灯白色常亮

   always   @(   posedge   ?clk_1Hz)
   begin
   ????   case   (car_status)
   ????????   4'b0001   :????????????????????????????????   //直行
   ????????   begin
   ????????????l_light?   <=   ?   1   ;
   ????????????r_light?   <=   ?   1   ;
   ????????????l_light_b?   <=   ?   1   ;
   ????????????r_light_b?   <=   ?   1   ;
   ????????   end
   ????????   4'b0010   :????????????????????????????????   //左转
   ????????   begin
   ????????????l_light?   <=   ?   ~   l_light;
   ????????????r_light?   <=   ?   1   ;
   ????????????l_light_b?   <=   ?   1   ;
   ????????????r_light_b?   <=   ?   1   ;
   ????????   end
   ????????   4'b0100   :????????????????????????????????   //右转
   ????????   begin
   ????????????l_light?   <=   ?   1   ;
   ????????????r_light?   <=   ?   ~   r_light;
   ????????????l_light_b?   <=   ?   1   ;
   ????????????r_light_b?   <=   ?   1   ;
   ????????   end
   ????????   4'b1000   :????????????????????????????????   //双闪
   ????????   begin
   ????????????l_light?   <=   ?   ~   l_light;
   ????????????r_light?   <=   ?   ~   r_light;
   ????????????l_light_b?   <=   ?   1   ;
   ????????????r_light_b?   <=   ?   1   ;
   ????????   end
   ??????????   4'b1111   :??????????????????????????????   //倒车
   ??????????   begin
   ????????????l_light?   <=   ?   0   ;
   ????????????r_light?   <=   ?   0   ;
   ????????????l_light_b?   <=   ?   0   ;
   ????????????r_light_b?   <=   ?   0   ;
   ??????????   end
   ????????   default   :
   ????????   begin
   ????????????l_light?   <=   ?   1   ;
   ????????????r_light?   <=   ?   1   ;
   ????????????l_light_b?   <=   ?   1   ;
   ????????????r_light_b?   <=   ?   1   ;
   ????????????????
   ????????   end
   ????   endcase
   end  

原文地址：https://www.cnblogs.com/codaland/p/11965649.html