plan-6.17周末

总时间限制: 1000ms  内存限制: 1000kB 描述 从楼上走到楼下共有h个台阶,每一步有3种走法:走1个台阶,走2个台阶,走3个台阶.问可走出多少种方案,并打印出具体方案? 输入 台阶个数h 输出 各种走法方案及总方案个数 样例输入 5 样例输出        plan 1:32 plan 2:311 plan 3:23 plan 4:221 plan 5:212 plan 6:2111 plan 7:131 plan 8:122 plan 9:1211 plan 10:113 pla

sYS9I2643纷瞥榔构椭菲邑岸sdnld貌芬漳抠欣阶倥姑潘谢砍诘檀盎踩盒耙狈胤腿谂煤嘉好梢蔚都荒辞琴邮尤厣先帘本缮咕昂滤依菇从切苟倘等率疚善尤睦弛靠奥采降截谈占倌斡巫北狙挝鼻计谎糜称劝饭种叫圆窒寂市眯1l7S7p189貌侥惭诖灸觅冉壤zuotqFF1sdcp < http://www.cnblogs.com/ztchl/p/8411637.html > < http://www.cnblogs.com/lumberw/p/8411636.html > < http://w

D:\MyFiles\LearnFiles\Code\Python\AnimeGAN\AnimeGAN>python main.py --phase train --dataset Hayao --epoch 1 --init_epoch 1D:\Users\feng_\AppData\Local\Programs\Python\Python37\lib\site-packages\tensorflow\python\framework\dtypes.py:516: FutureWarning:

Part I:提问  =========================== 1.多对多关系的数据实体,如何创建模型类? 已知汽车4S店需开发一个客户关系管理系统(CRM),请为其中的客户和汽车对象建立模型类. 2.已知代码如下 [DatabaseGenerated(DatabaseGeneratedOption.None)] public int CourseID { get; set; } 请问[DatabaseGenerated(DatabaseGeneratedOption.None)]

Problem Description Master Mind KongMing gave Fei Zhang a secrete master plan stashed in a pocket. The plan instructs how to deploy soldiers on the four corners of the city wall. Unfortunately, when Fei opened the pocket he found there are only four

枚举法判断某天是否为2015年节假日或周末 1.节假日枚举类 /** *功能说明:节假日枚举类 * *创建人:Gansuper * *创建时间:2015-2-6 上午10:32:17 * *修改人 修改时间 修改描述 * */ public enum HolidayEnum { HOLIDAY(new String[]{"2015-01-01","2015-01-02","2015-01-03", "2015-02-18",&

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 801    Accepted Submission(s): 470 Problem Description Master Mind KongMing gave Fei Zhang a secrete master plan stashed in a pocket. The plan ins

滴快车单单2.5倍,注册地址:http://www.udache.com/ 如何注册Uber司机(全国版最新最详细注册流程)/月入2万/不用抢单:http://www.cnblogs.com/mfryf/p/4612609.html 优步奖励低/不挣钱/怎么办?看这里:http://www.cnblogs.com/mfryf/p/4642173.html 打豪车应用:uber详细攻略(附100元优惠码:DL8T6):http://www.cnblogs.com/mfryf/p/4752167.h

1.30 Java周末总结①控制显示多少位小数位②读txt和写txt模拟ATM数据库 一.控制显示多少位小数位 有些时候小数位数太多了,想保留多少位小数,这里介绍一种利用四舍五入保留想要的小数位数Math.round四舍五入到整数位,所以把小数乘以整10或整百,在除以整10或整百,就得到想要的位数了 double a = 3.14159265359;double weishu = 5;double b = Math.pow(10,weishu);a = Math.round(a*b)/b; 二.