多条件排序可以通过在order by语句后面使用case when then条件语句来实现。

select * from 表名 ORDER BY case when 条件 then 0 else 1 end

例子：

1.创建表case_test

共有id，case_type，case_location，case_way四个字段。

2.导入数据：

INSERT INTO "XIANGZH"."case_test" VALUES (‘1‘, ‘盗窃案‘, ‘台东‘, ‘技术开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘88‘, ‘谋杀案‘, ‘台东‘, ‘技术开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘99‘, ‘盗窃案‘, ‘江西路‘, ‘技术开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘5‘, ‘盗窃案‘, ‘台东‘, ‘暴力开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘6‘, ‘盗窃案‘, ‘江西路‘, ‘暴力开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘7‘, ‘谋杀案‘, ‘台东‘, ‘暴力开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘8‘, ‘谋杀案‘, ‘江西路‘, ‘技术开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘9‘, ‘谋杀案‘, ‘江西路‘, ‘暴力开锁‘);
INSERT INTO "XIANGZH"."case_test" VALUES (‘10‘, ‘盗窃案‘, ‘台东‘, ‘技术开锁‘);

未排序截图：

3.多条件分组排序

select * from "case_test" ORDER BY
case when "case_type"=‘盗窃案‘ then 0 else 1 end,
case when "case_location" = ‘台东‘ then 0 else 1 end,
case when "case_way" = ‘技术开锁‘ then 0 else 1 end ASC

查询结果是按照条件分组排序，截图：

4.满足条件个数排序

select * from "case_test" ORDER BY
case
when "case_type"=‘盗窃案‘ and "case_location" = ‘台东‘ and "case_way" = ‘技术开锁‘ then 0
when "case_type"=‘盗窃案‘ and "case_location" = ‘台东‘ then 1
when "case_type"=‘盗窃案‘ and "case_way" = ‘技术开锁‘ then 2
when "case_location" = ‘台东‘ and "case_way" = ‘技术开锁‘ then 3
when "case_type"=‘盗窃案‘ then 4
when "case_location" = ‘台东‘ then 5
when "case_way" = ‘技术开锁‘ then 6
else 7
end

查询结果是按照满足条件的个数排序，截图：

如果有更合理的sql写法，欢迎留言讨论。

参考：

ORACLE按条件排序的例子

Oracle怎么按条件排序