Problem:
Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.
The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘.
A partially filled sudoku which is valid.
Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.
Solution:
根据数独游戏的规则，一个9行9列的棋盘，每行每列和每一个3*3的小方格都不能有重复的数字，并且数字只能是0-9，逐一判断这些规则是否满足即可
题目大意：
给定一个二维数组，判定是否满足数独游戏的规则，不需要判断没有填上的点，只需要判断已经有的数字是否满足
Java源代码（320ms）：
public class Solution {
public boolean isValidSudoku(char[][] board) {
int i,j,k,l;
if(board.length!=9 || board[0].length!=9)return false;
int[] map;
for(i=0;i<9;i++){
map= new int[10];
for(j=0;j<9;j++){
if(board[i][j]=='.')continue;
if(board[i][j]<'0' || board[i][j]>'9')return false;
int num=board[i][j]-'0';
if(map[num]==1)return false;
map[num]=1;
}
}
for(j=0;j<9;j++){
map=new int[10];
for(i=0;i<9;i++){
if(board[i][j]=='.')continue;
int num=board[i][j]-'0';
if(map[num]==1)return false;
map[num]=1;
}
}
for(i=0;i<9;i+=3){
for(j=0;j<9;j+=3){
map=new int[10];
for(k=i;k<i+3;k++){
for(l=j;l<j+3;l++){
if(board[k][l]=='.')continue;
int num=board[k][l]-'0';
if(map[num]==1)return false;
map[num]=1;
}
}
}
}
return true;
}
}
C语言源代码（4ms）：
bool isValidSudoku(char** board, int boardRowSize, int boardColSize) {
int map[10],i,j,k,l,num;
if(boardRowSize!=9 || boardColSize!=9)return false;
for(i=0;i<9;i++){
memset(map,0,sizeof(map));
for(j=0;j<9;j++){
if(board[i][j]=='.')continue;
if(board[i][j]<'0' || board[i][j]>'9')return false;
num=board[i][j]-'0';
if(map[num]!=0)return false;
map[num]=1;
}
}
for(j=0;j<9;j++){
memset(map,0,sizeof(map));
for(i=0;i<9;i++){
if(board[i][j]=='.')continue;
num=board[i][j]-'0';
if(map[num]!=0)return false;
map[num]=1;
}
}
for(i=0;i<9;i+=3){
for(j=0;j<9;j+=3){
memset(map,0,sizeof(map));
for(k=i;k<i+3;k++){
for(l=j;l<j+3;l++){
if(board[k][l]=='.')continue;
num=board[k][l]-'0';
if(map[num]!=0)return false;
map[num]=1;
}
}
}
}
return true;
}
C++源代码（12ms）：
class Solution {
public:
bool isValidSudoku(vector<vector<char>>& board) {
int i,j,k,l,map[10];
if(board.size()!=9 || board[0].size()!=9)return false;
for(i=0;i<9;i++){
memset(map,0,sizeof(map));
for(j=0;j<9;j++){
if(board[i][j]=='.')continue;
if(board[i][j]<'0' || board[i][j]>'9')return false;
int num=board[i][j]-'0';
if(map[num])return false;
map[num]=1;
}
}
for(j=0;j<9;j++){
memset(map,0,sizeof(map));
for(i=0;i<9;i++){
if(board[i][j]=='.')continue;
int num=board[i][j]-'0';
if(map[num])return false;
map[num]=1;
}
}
for(i=0;i<9;i+=3){
for(j=0;j<9;j+=3){
memset(map,0,sizeof(map));
for(k=i;k<i+3;k++){
for(l=j;l<j+3;l++){
if(board[k][l]=='.')continue;
int num=board[k][l]-'0';
if(map[num])return false;
map[num]=1;
}
}
}
}
return true;
}
};
Python源代码（104ms）：
class Solution:
# @param {character[][]} board
# @return {boolean}
def isValidSudoku(self, board):
if len(board)!=9 or len(board[0])!=9:return False
for i in range(9):
map=[0 for k in range(10)]
for j in range(9):
if board[i][j]=='.':continue
if board[i][j]<'0' or board[i][j]>'9':return False
num = ord(board[i][j])-ord('0')
if map[num]==1:return False
map[num]=1
for j in range(9):
map=[0 for k in range(10)]
for i in range(9):
if board[i][j]=='.':continue
num = ord(board[i][j])-ord('0')
if map[num]==1:return False
map[num]=1
for i in range(0,9,3):
for j in range(0,9,3):
map=[0 for k in range(10)]
for k in range(i,i+3):
for l in range(j,j+3):
if board[k][l]=='.':continue
num = ord(board[k][l])-ord('0')
if map[num]==1:return False
map[num]=1
return True
时间： 2024-10-15 07:48:23