Code Signal_练习题_variableName

Correct variable names consist only of English letters, digits and underscores and they can‘t start with a digit.

Check if the given string is a correct variable name.

Example

    • For name = "var_1__Int", the output should be
      variableName(name) = true;
    • For name = "qq-q", the output should be
      variableName(name) = false;
    • For name = "2w2", the output should be
      variableName(name) = false.

我的解答:

def variableName(name):
    dict = {‘word‘:‘qwertyuiopasdfghjklzxcvbnm‘, ‘digit‘:‘0123456789‘, ‘underline‘:‘_‘}
    if name[0].lower() in dict[‘word‘] or name[0] in dict[‘underline‘]:
        for i in name:
            if i.lower() in dict[‘word‘] or i in dict[‘underline‘] or i in dict[‘digit‘]:
                pass
            else:
                return False
        return True
    else:
        return False

def variableName(name):
    return name.isidentifier()

膜拜大佬

原文地址:https://www.cnblogs.com/YD2018/p/9470193.html

时间: 2024-10-15 01:32:51

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