C语言获取系统当前时间转化成时间字符串

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#include <stdio.h>

#include <time.h>

int getNowTime(char *nowTime)

{

char acYear[5] = {0};

char acMonth[5] = {0};

char acDay[5] = {0};

char acHour[5] = {0};

char acMin[5] = {0};

char acSec[5] = {0};

time_t now;

struct tm* timenow;

time(&now);

timenow = localtime(&now);

strftime(acYear,sizeof(acYear),"%Y",timenow);

strftime(acMonth,sizeof(acMonth),"%m",timenow);

strftime(acDay,sizeof(acDay),"%d",timenow);

strftime(acHour,sizeof(acHour),"%H",timenow);

strftime(acMin,sizeof(acMin),"%M",timenow);

strftime(acSec,sizeof(acSec),"%S",timenow);

strncat(nowTime, acYear, 4);

strncat(nowTime, acMonth, 2);

strncat(nowTime, acDay, 2);

strncat(nowTime, acHour, 2);

strncat(nowTime, acMin, 2);

strncat(nowTime, acSec, 2);

return 0;

}

int main(int argc, char *argv[])

{

char nowTime[32] = {0};

getNowTime(nowTime);

printf("nowTime is %s.\n", nowTime);

return 0;

}