获取数据库中,所有用户表中每一列名和其数据类型。
SELECT OBJECT_NAME(c.OBJECT_ID) AS [Table_Name], c.[name] AS [Column_Name] ,t.[name] AS [Data_Type_Name] FROM sys.columns AS c LEFT JOIN SYSOBJECTS AS s ON (c.[object_id] = s.[id]) LEFT JOIN sys.types AS t ON (c.[user_type_id]=t.[user_type_id]) WHERE s.xtype = ‘U‘
Source Code
原文地址:https://www.cnblogs.com/insus/p/12131525.html
时间: 2024-12-17 13:12:25