这道题也很简单,只要把二叉树按照宽度优先的策略遍历一遍,就可以解决问题,采用递归方法越是简单。
下面是AC代码:
1 /**
2 * Sum Root to Leaf Numbers
3 * 采用递归的方法,宽度遍历
4 */
5 int result=0;
6 public int sumNumbers(TreeNode root){
7
8 bFSearch(root,0);
9 return result;
10 }
11 private void bFSearch(TreeNode root, int sum){
12 //a path has been finished
13 if(root.left == null && root.right == null)
14 {
15 result += sum*10+root.val;
16 return;
17 }
18 if(root.left !=null)
19 bFSearch(root.left, sum*10+root.val);
20 if(root.right != null)
21 bFSearch(root.right, sum*10+root.val);
22 }
LeetCode OJ - Sum Root to Leaf Numbers,布布扣,bubuko.com
时间: 2024-10-06 00:38:56