lintcode

public class Solution {
    /**
     * @param s: The first string
     * @param b: The second string
     * @return true or false
     */
    public boolean anagram(String s, String t) {
        // write your code here
        Map<String , Integer> sMap = new HashMap<String , Integer>();
        Map<String , Integer> tMap = new HashMap<String , Integer>();

        if(s.length() != t.length()){
            return false;
        }

        int i=0;
        int wCount=0;
        while(i<s.length()){
            if(sMap.containsKey(s.substring(i,i+1))){
                wCount=sMap.get(s.substring(i,i+1)).intValue();
                wCount++;
                sMap.put(s.substring(i,i+1) , new Integer(wCount));
            }
            else{

                sMap.put(s.substring(i,i+1) , new Integer(1));
            }
            i++;
        }

        i=0;
        while(i<t.length()){
            if(tMap.containsKey(t.substring(i,i+1))){
                wCount=tMap.get(t.substring(i,i+1)).intValue();
                wCount++;
                tMap.put(t.substring(i,i+1) , new Integer(wCount));
            }
            else{

                tMap.put(t.substring(i,i+1) , new Integer(1));
            }
            i++;
        }

        Set sEntrySet = sMap.entrySet();
        Iterator sIterator = sEntrySet.iterator();

        while(sIterator.hasNext()){
            Map.Entry pair = (Map.Entry)sIterator.next();
            if(! tMap.containsKey(pair.getKey()) ){
                return false;
            }else{
                if(((Integer)tMap.get(pair.getKey())).intValue() != ((Integer)(pair.getValue())).intValue()){
                    return false;
                }
            }

        }

        return true;

    }
}