http://poj.org/problem?id=2761 (题目链接)
题意:求区间第K大。
Solution
和poj2104一模一样。
主席树代码:
// poj2761 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #define LL long long #define inf 2147483640 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int M=10000010; int a[M],b[M],lson[M],rson[M],T[M],c[M]; int n,tot,q; int build(int l,int r) { int k=++tot; c[k]=0; if (l==r) return k; int mid=(l+r)>>1; lson[k]=build(l,mid); rson[k]=build(mid+1,r); return k; } int update(int l,int r,int K,int x) { int k=++tot; c[k]=c[K]+1; if (l==r) return k; int mid=(l+r)>>1; if (x<=mid) { rson[k]=rson[K]; lson[k]=update(l,mid,lson[K],x); } else { lson[k]=lson[K]; rson[k]=update(mid+1,r,rson[K],x); } return k; } int query(int l,int r,int k,int K,int x) { if (l==r) return l; int mid=(l+r)>>1; if (c[lson[K]]-c[lson[k]]>=x) return query(l,mid,lson[k],lson[K],x); else return query(mid+1,r,rson[k],rson[K],x-c[lson[K]]+c[lson[k]]); } int main() { while (scanf("%d%d",&n,&q)!=EOF) { tot=0; for (int i=1;i<=n;i++) scanf("%d",&a[i]),b[i]=a[i]; sort(b+1,b+1+n); int m=unique(b+1,b+1+n)-b-1; T[0]=build(1,m); for (int i=1;i<=n;i++) { int x=lower_bound(b+1,b+1+m,a[i])-b; T[i]=update(1,m,T[i-1],x); } while (q--) { int l,r,k; scanf("%d%d%d",&l,&r,&k); printf("%d\n",b[query(1,m,T[l-1],T[r],k)]); } } return 0; }
分块+莫队代码:
// poj2761 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<cmath> #define LL long long #define inf 2147483640 #define Pi acos(-1.0) #define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout); using namespace std; const int maxn=100010; struct ask {int l,r,k,id;}t[maxn]; struct data {int w,id;}a[maxn]; int pos[maxn],cnts[maxn],b[maxn],p[maxn],ma[maxn],ans[maxn],n,m,s,q,block; bool wcmp(data a,data b) { return a.w<b.w; } bool poscmp(ask a,ask b) { return pos[a.l]==pos[b.l] ? a.r<b.r : pos[a.l]<pos[b.l]; } void build() { block=(int)sqrt((float)m); for (int i=1;i<=m;i++) pos[i]=(i-1)/block+1; s=m%block ? m/block+1 : m/block; for (int i=1;i<=s;i++) cnts[i]=0; } void update(int x,int val) { cnts[pos[x]]+=val; b[x]+=val; } int query(int k) { int tot=0; for (int i=1;i<=s;i++) { tot+=cnts[i]; if (tot>=k) { tot-=cnts[i]; for (int j=(i-1)*block+1;j<=min(i*block,m);j++) { if (tot+b[j]>=k) return ma[j]; else tot+=b[j]; } } } } int main() { scanf("%d%d",&n,&q); for (int i=1;i<=n;i++) scanf("%d",&a[i].w),a[i].id=i; for (int i=1;i<=q;i++) scanf("%d%d%d",&t[i].l,&t[i].r,&t[i].k),t[i].id=i; sort(a+1,a+1+n,wcmp); m=0; ma[p[a[1].id]=++m]=a[1].w; for (int i=2;i<=n;i++) { if (a[i].w!=a[i-1].w) m++; ma[p[a[i].id]=m]=a[i].w; } block=(int)sqrt((float)n); for (int i=1;i<=n;i++) pos[i]=(i-1)/block+1; sort(t+1,t+1+q,poscmp); build(); for (int l=1,r=0,i=1;i<=q;i++) { for (;r<t[i].r;r++) update(p[r+1],1); for (;r>t[i].r;r--) update(p[r],-1); for (;l<t[i].l;l++) update(p[l],-1); for (;l>t[i].l;l--) update(p[l-1],1); ans[t[i].id]=query(t[i].k); } for (int i=1;i<=q;i++) printf("%d\n",ans[i]); return 0; }
时间: 2024-09-28 02:47:13