Linux Shell编程实战---计算特定目录下前10个大文件

计算特定目录下前10个大文件

在给定的目录下，想知道有哪些大文件存在，取前十个，按文件大小排行

(1)、使用awk来实现

#!/bin/bash

path=/root/shell

find $path-type f | awk ‘{

var=$0

"ls -l "var |getline var1

split(var1,a," ")

filename=a[9]

filesize=a[5]

printf("%s %s\n",filename,filesize)| "sort -k2 -n -r|head -10"

}

‘

上面的写法在文件较多的时候可能会引起内存溢出。

改进一下如下：

#!/bin/bash

path=/root/shell

echo >r2.txt

find $path-type f | awk ‘{

var=$0

"ls -l "var |getline var1

split(var1,a," ")

filename=a[9]

filesize=a[5]

printf("%s %s\n",filename,filesize)

}

‘>r2.txt

cat r2.txt|sort -k2 -n -r | head -10

(2)、使用while来实现

#!/bin/bash

path=/root/shell

echo >r1.txt

find $path-type f|while read line

do

filename=`ls -l $line|awk ‘{print $9}‘`

filesize=`ls -l $line|awk ‘{print $5}‘`

echo $filename $filesize>>r1.txt

done

cat r1.txt|sort -k2 -n -r | head -10