dinner vs supper

题目要求是这样的: 实现一个LazyMan,可以按照以下方式调用:LazyMan("Hank")输出:Hi! This is Hank! LazyMan("Hank").sleep(10).eat("dinner")输出Hi! This is Hank!//等待10秒..Wake up after 10Eat dinner~ LazyMan("Hank").eat("dinner").eat("s

题目如下: 实现一个LazyMan,可以按照以下方式调用: LazyMan("Hank")输出: Hi! This is Hank! LazyMan("Hank").sleep(10).eat("dinner")输出 Hi! This is Hank! //等待10秒.. Wake up after 10 Eat dinner~ LazyMan("Hank").eat("dinner").eat("

let index = 0; let stack = []; function next() { let fn = stack[index]; index++; if(typeof fn === 'function'){ fn(); } } function fn1() { console.log(1) next() } function fn2() { setTimeout(function() { console.log(2) next() },0) } function fn3() { c

原文:如何实现一个LazyMan 面试题目 实现一个LazyMan,可以按照以下方式调用: LazyMan('Hank'),输出: Hi, This is Hank! LazyMan('Hank').sleep(5).eat('dinner'),输出: Hi, This is Hank! // 等待5秒 Weak up after 10 Eat dinner ~ LazyMan('Hank').eat('dinner').eat('supper'),输出 Hi, this is Hank! Ea

前言 笔者昨天在做某公司的线上笔试题的时候遇到了最后一道关于如何实现LazyMan的试题,题目如下 实现一个LazyMan,可以按照以下方式调用:LazyMan("Hank")输出:Hi! This is Hank! LazyMan("Hank").sleep(10).eat("dinner")输出Hi! This is Hank!//等待10秒..Wake up after 10Eat dinner~ LazyMan("Hank&qu

题目 实现一个LazyMan,可以按照以下方式调用: LazyMan("Hank")输出: Hi! This is Hank! LazyMan("Hank").sleep(10).eat("dinner")输出 Hi! This is Hank! //等待10秒.. Wake up after 10 Eat dinner~ LazyMan("Hank").eat("dinner").eat("su

Coach Pang loves his boyfriend Uncle Yang very much. Today is Uncle Yang's birthday, Coach Pang wants to have a romantic candlelit dinner at Uncle Yang's house and he has to arrive there in T minutes.  There are N houses in their city numbered from 1

Fox Ciel is participating in a party in Prime Kingdom. There are n foxes there (include Fox Ciel). The i-th fox is ai years old. They will have dinner around some round tables. You want to distribute foxes such that: Each fox is sitting at some table

supper应用场景: 子类具有特殊功能,子类重写父类的方法,并且想保留父类的方法时使用supper关键字(因为如果采用self的话,则会导致死循环) supper的注意点: supper会自动区分类方法跟对象方法,如果在类方法中使用supper调用对象方法,那么会报错! supper与self关键字的区别: supper关键字是直接在父类中查找相应的方法:而self关键字是在子类中查找方法,如果找不到则在父类中进行查找