二进制练习小游戏

　　今天恶补汇编，发下脑袋变迟钝了，所以写了个小程序，练习一下二进制转换，巩固记忆~~

　　先来看看二进制（Binary）、十进制（Decimal）、十六进制（Binary）的关系表格

　　根据对应关系，写了如下小代码，亦可以统计成功率

 1 #include <iostream>
 2 #include <ctime>
 3 #include <cstdlib>
 4 #include <string>
 5 #include <bitset>
 6
 7 using namespace std;
 8
 9 int main(int argc, char *argv[])
10 {
11     cout << "You must enter a 4-digit binary number." << endl;
12     cout << "If you enter ‘q‘ or ‘Q‘, then the game over~"<< endl;
13     cout << "Now, let‘s start the game!" << endl;
14     cout << endl;
15
16     unsigned long correctCount = 0;
17     unsigned long totalCount = 0;
18     srand(time(NULL));
19     do{
20         unsigned long v = rand() % 16;
21         if(0 == (rand() - (v << 1)) % 2)
22             cout << hex << uppercase << v << " = ";
23         else
24             cout << v << " = ";
25
26         string str;
27         cin >> str;
28
29         if(0 == str.compare("q") || 0 == str.compare("Q")){
30             cout << endl;
31             break;
32         }
33
34         if(str.size() > 4){
35             cout << "Please enter a valid 4-digit binary number" << endl;
36         }else{
37             try{
38                 bitset<4> foo(str);
39
40                 totalCount++;
41                 if(foo.to_ulong() == v){
42                         correctCount++;
43                     cout << "^_-! Bingo!" << endl;
44                 }else
45                     cout << "-_-! Once again!" << endl;
46             }catch(...){
47                 cout << "Please enter the binary format!" << endl;
48             }
49         }
50
51         cout << endl;
52     }while(1);
53
54     if(totalCount > 0)
55         cout << "Correct Rate: " << correctCount / double(totalCount) * 100 << "%" << endl;
56
57     cout << "Bye-bye ^_^!" << endl;
58     return 0;
59 }