一个简单的使用遍历的方式进行DataTable 的拆分
private static List<DataTable> DataTableSplite(DataTable dt, int modcounts) { List<DataTable> list = new List<DataTable>(); int counts = dt.Rows.Count / modcounts; /// 取整数个数 int mod = dt.Rows.Count % modcounts; /// 余数 if (mod > 0) { int index = 0; /// 处理拆分倍数的部分 for (int i = 0; i < counts; i++) { DataTable dt1 = dt.Clone(); dt1.TableName = "count" + i; for (int j = index * modcounts; j < (index + 1) * modcounts; j++) { DataRow newrow = dt.NewRow(); DataRow row1 = dt.Rows[j]; newrow["name"] = row1["name"]; newrow["age"] = row1["age"]; dt1.Rows.Add(newrow.ItemArray); } index++; list.Add(dt1); } /// 处理余数部分的组合 DataTable dt2 = dt.Clone(); dt2.TableName = "modetable"; for (int i = counts * modcounts; i < dt.Rows.Count; i++) { DataRow newrow = dt.NewRow(); DataRow row1 = dt.Rows[i]; newrow["name"] = row1["name"]; newrow["age"] = row1["age"]; dt2.Rows.Add(newrow.ItemArray); } list.Add(dt2); } else { /// 余数为0 的情况处理 int index = 0; for (int i = 0; i < counts; i++) { DataTable dt1 = dt.Clone(); dt1.TableName = "modetable"; for (int j = index * modcounts; j < (index + 1) * modcounts; j++) { DataRow newrow = dt.NewRow(); DataRow row1 = dt.Rows[j]; newrow["name"] = row1["name"]; newrow["age"] = row1["age"]; dt1.Rows.Add(newrow.ItemArray); } index++; list.Add(dt1); } } return list; }
实现的方式比较简单,同时也可以使用linq 的方式进行
代码如下:
private static List<DataTable> DataTableSplite2(DataTable dt, int modcounts) { int counts = dt.Rows.Count / modcounts; /// 取整数个数 List<DataTable> list = new List<DataTable>(); /// int index = 0; for (int i = 0; i < counts + 1; i++) { list.Add(dt.AsEnumerable().Skip(index * modcounts).Take(modcounts).CopyToDataTable()); index++; } return list; }
代码更少。
时间: 2024-10-19 10:34:36