1058. A+B in Hogwarts (20)
时间限制
50 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it‘s easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
提交代码
1 #include<cstdio> 2 #include<stack> 3 #include<cstring> 4 #include<iostream> 5 #include<stack> 6 #include<set> 7 #include<map> 8 using namespace std; 9 int dight[3]; 10 int main(){ 11 //freopen("D:\\INPUT.txt","r",stdin); 12 int a,b,c; 13 scanf("%d.%d.%d",&a,&b,&c); 14 scanf("%d.%d.%d",&dight[0],&dight[1],&dight[2]); 15 dight[0]+=a; 16 dight[1]+=b; 17 dight[2]+=c; 18 dight[1]+=dight[2]/29; 19 dight[2]%=29; 20 dight[0]+=dight[1]/17; 21 dight[1]%=17; 22 printf("%d.%d.%d\n",dight[0],dight[1],dight[2]); 23 return 0; 24 }