二叉树的层序遍历、二叉树叶节点输出算法、求二叉树的高度、层序创建一棵二叉树

二叉树的层序遍历

 1 void LevelorderTraversal(BinTree BT)
 2 {
 3     std::queue<BinTree> Queue;
 4     BinTree T;
 5     if (!BT)
 6         return;            //若是空树则直接返回
 7     Queue.push(BT);
 8     while (!Queue.empty())
 9     {
10         T = Queue.front();
11         Queue.pop();
12         printf("%c ", T->Data);
13         if (T->Left) Queue.push(T->Left);
14         if (T->Right) Queue.push(T->Right);
15     }
16 }

二叉树叶节点输出算法

 1 void InorderTraversal(BinTree BT, int Depth)
 2 {
 3     if (BT)
 4     {
 5                if(!BT->Left && !BT->Right)
 6             printBinTree(BT, Depth);
 7         InorderTraversal(BT->Left, Depth + 1);
 8         InorderTraversal(BT->Right, Depth + 1);
 9
10         //printf("%c", BT->Data);
11
12     }
13 }    

求二叉树的高度

 1 int GetHeight(BinTree BT)
 2 {
 3     int HL, HR, MaxH;
 4     if (BT)
 5     {
 6         HL = GetHeight(BT->Left);        //求左子树的高度
 7         HR = GetHeight(BT->Right);        //求右子树的高度
 8         MaxH = HL > HR ? HL : HR;        //取左右子树较大的高度
 9         return (MaxH + 1);            //返回树的高度
10     }
11     else
12         return 0;
13 }

层序创建一棵二叉树

 1 BinTree CreateBinTree()
 2 {
 3     ElementType dt;
 4     BinTree BT, T;
 5     std::queue<BinTree> Q;
 6     scanf_s("%c", &dt);
 7     getchar();
 8     if (dt != NoInfo)
 9     {
10         BT = (BinTree)malloc(sizeof(struct TNode));
11         BT->Data = dt;
12         BT->Left = BT->Right = NULL;
13         Q.push(BT);
14     }
15     else
16         return NULL;
17     while (!Q.empty())
18     {
19         T = Q.front();
20         Q.pop();
21         scanf_s("%c", &dt);
22         getchar();
23         if (dt == NoInfo)
24             T->Left = NULL;
25         else
26         {
27             T->Left = (BinTree)malloc(sizeof(struct TNode));
28             T->Left->Data = dt;
29             T->Left->Left = T->Left->Right = NULL;
30             Q.push(T->Left);
31         }
32         scanf_s("%c", &dt);
33         getchar();
34         if (dt == NoInfo)
35             T->Right = NULL;
36         else
37         {
38             T->Right = (BinTree)malloc(sizeof(struct TNode));
39             T->Right->Data = dt;
40             T->Right->Left = T->Right->Right  = NULL;
41             Q.push(T->Right);
42         }
43     }
44     return BT;
45 }

原文地址：https://www.cnblogs.com/hi3254014978/p/9747381.html