Python:简单的登陆GUI界面

import tkinterimport sysimport re

top = tkinter.Tk()top.geometry(‘400x170+350+150‘)top.wm_title(‘综合实例‘)

def validateText():    val = entry1.get()    if re.findall(‘^[0-9a-zA-Z_]{1,}$‘,str(val)):        return True    else:        label3[‘text‘] = ‘用户名只能包含字母、数字、下划线‘        return False

def anw_button():    if str.upper(entry1.get()) == "123456" and str.upper(entry2.get()) ==‘123456‘:        label3[‘text‘] = ‘登陆成功‘    else:        label3[‘text‘] = ‘用户名或密码错误，请重新输入！‘

label1 = tkinter.Label(top,text = ‘用户名:‘,font = (‘宋体‘,‘18‘))label1.grid(row = 0,column = 0)label2 = tkinter.Label(top,text = ‘密码:‘,font = (‘宋体‘,‘18‘))#集合为另一种形式的字典label2 .grid(row = 1 ,column = 0)v = tkinter.StringVar()entry1 = tkinter.Entry(top,font = (‘宋体‘,‘18‘),textvariable = v,\                        validate = ‘focusout‘,validatecommand = validateText)

entry1.grid(row = 0,column = 1)entry1.focus_force()entry2 = tkinter.Entry(top,font = (‘宋体‘,‘18‘),show = ‘*‘)

entry2.grid(row = 1,column = 1)button1 = tkinter.Button(top,text = ‘登陆‘,font = (‘宋体‘,‘18‘),\                         command = anw_button)button1.grid(row = 2,column = 0,padx = 50,pady = 10)button2 = tkinter.Button(top,text = ‘退出‘, font = (‘宋体‘,‘18‘),\                         command = sys.exit)

button2.grid(row = 2,column = 1,padx = 80,pady = 10)label3 = tkinter.Label(top,text = ‘信息提示区‘,font = (‘华文新魏‘,‘16‘),\                       relief = ‘ridge‘,width = 30)label3.grid(row = 3,column = 0,padx = 10,pady = 10,columnspan = 2,sticky = ‘s‘)top.mainloop()

原文地址：https://www.cnblogs.com/Osword/p/9693030.html