jquery Bootstrap 弹出框（Popover）显示html内容，URL，div等

实现效果：

其实有个关键点：

data-container="body" data-html="true" 注意下就可以了

<button type="button" class="btn btn-success" title="Popover title"
            data-container="body" data-html="true" data-toggle="popover" data-placement="bottom"
            data-content=‘

            <div id="popover-content"> <form role="form" method="post"> <div class="form-group"> <label>Start time?</label> <div class="input-group date" id="datetimepicker1"> <input type="text" class="form-control" placeholder="Start Date time of event" /> <span class="input-group-addon"> <span class="glyphicon glyphicon-calendar"></span> </span> </div> </div> <div class="form-group"> <label>End time?</label> <div class="input-group date" id="datetimepicker2"> <input type="text" class="form-control" placeholder="End Date time" /> <span class="input-group-addon"> <span class="glyphicon glyphicon-calendar"></span> </span> </div> </div> <div class="form-group"> <button class="btn btn-primary btn-block">Search between dates</button> </div> </form> </div>

            ‘>
        底部的 Popover
    </button>

要是没加 data-container="body" data-html="true" ，那就这样了：

原文地址：http://blog.51cto.com/ipcpu/2178601