Slash

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)

Problem Description

The American English slash (/) is a punctuation mark. In the early modern period, in the Fraktur script, which was widespread through Europe in the Middle Ages, one slash(/) represented a comma, while two slashes (//) represented
a dash.

With the wide use of computers, slash appeared far more than at any previous time in history. On Unix-like systems and in URLs, the slash is to separate directory and file components of a path:

/home/whuacm/chaeyeon/Sherlockpp.jpg

http://acm.whu.edu.cn/

But in Windows systems, it uses (\) to separate directory and file components of a path:

C:\Users\v-yungao\Music\Shake

That really confuses me. Could you help me to judge if the string I wrote is right.

Please notice that I would only make a mistake by changing (\) to (/) or (/) to (\). All the strings were constituted by a-z, A-Z, 0-9, (.) , (\) and (/), no other characters would appear in the strings.

A string of URL always begins with “[a-zA-Z]+://” (Notice (/) maybe changed to (\) ), in which “[a-zA-Z]+” represents any non-empty string of letters.

Windows path begins with “[a-zA-Z]:\” (Notice (\) maybe changed to (/)), in which “[a-zA-Z]” means an English letter. (e.g. “C:\\windows” is a URL not a Windows path)

The path of Unix-like system begins with (/) or (\).

I’ll give you some strings, can you tell me which type those strings belong to and those correct forms.

Input

The first line consists of an integer T, indicating the number of strings.

The next T lines, each line consists of a single non-empty string. All of those are really data from our daily life.

Output

For each string:

If it belongs to a path in Unix-like systems, output “It’s a path in Unix-like systems!” in a new line and the correct string in the next line.

If it belongs to a path in Windows system, output “It’s a path in Windows system!” in a new line and the correct string in the next line.

If it’s a URL, output “It’s a URL!” in a new line and the correct string in the next line.

The kind of each input string can be uniquely determined.

Constrains

0 < T <= 20

The length of each string will not be longer than 50.

Sample Input

4
http://acm.whu.edu.cn/felioj
http:/\acm.whu.edu.cn/11111011001/
\home\whuacm\Slash\yama
Z:\movie/chaeyeon

Sample Output

It‘s a URL!
http://acm.whu.edu.cn/felioj
It‘s a URL!
http://acm.whu.edu.cn/11111011001/
It‘s a path in Unix-like systems!
/home/whuacm/Slash/yama
It‘s a path in Windows system!
Z:\movie\chaeyeon

告诉T个字符串，判断是三种类型中的哪一种，但是可能由于手抖把 / 和\  打错；

URL就是以/或者\开头

Unix就是一个字符串然后跟两个杠杠

Windows就是一个字符串后面跟一个杠杠

两个杠杠实际上是一样的

只是windows输出全部是 \

其他两种全部是 /

#include <iostream>
#include <stdio.h>
#include <string>
#include <cstring>
#include <cmath>
#include <algorithm>
#define N 100
using namespace std;

char s[N];
int T;

 char b[N];

int main()
{
    while(~scanf("%d",&T))
    {
        while(T--)
        {
            scanf("%s",s);
            int len=strlen(s);

            if( (s[0]>='a'&&s[0]<='z')||(s[0]>='A'&&s[0]<='Z')  )
            {
                int ff=0;
                int i=0;
                for(i=0;i<len;i++)
                {
                    if(s[i]=='/'||s[i]=='\\')
                    {
                        if(s[i+1]=='\\'||s[i+1]=='/')
                            ff=1;//URL

                        break;
                    }
                    else
                    b[i]=s[i];
                }
                if(ff==1)
                {
                    b[i]='/';
                    i++;
                    b[i]='/';
                }
                else
                b[i++]='\\';

                for(int j=i;j<len;j++)
                {
                    if(s[j]=='\\'||s[j]=='/')
                    {
                        if(ff)
                        b[j]='/';
                        else b[j]='\\';
                    }
                    else
                    b[j]=s[j];

                }
                if(ff)
                cout<<"It's a URL!"<<endl;
                else
                cout<<"It's a path in Windows system!"<<endl;

                for(int k=0;k<len;k++)
                cout<<b[k];

            }
            else
            {
                cout<<"It's a path in Unix-like systems!"<<endl;

                for(int i=0;i<len;i++)
                {
                    if(s[i]=='/'||s[i]=='\\')
                    cout<<'/';
                    else  cout<<s[i];
                }
            }
            cout<<endl;

        }
    }
    return 0;
}