Problem Description
Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has only one real numbers Y.(0 < Y <1e10)
Output
Just the minimum value (accurate up to 4 decimal places),when x is between 0 and 100.
Sample Input
2 100 200
Sample Output
-74.4291 -178.8534
#include <stdio.h> #include <math.h> int y; double fun1(double x) { return 42*pow(x,6) + 48*pow(x,5) + 21*x*x + 10*x - y; } double fun2(double x) { return 6*pow(x,7) + 8*pow(x,6) + 7*x*x*x + 5*x*x-y*x; } int main() { int T; scanf("%d",&T); while(T--) { scanf("%d",&y); double left=0,right=100,middle; while(right-left>=1e-10) { middle=(left+right)/2; if(fun1(middle)>0) right=middle; else left=middle; } printf("%.4lf\n",fun2(left)); } return 0; }
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时间: 2024-08-02 11:01:31