The first assignment

问题描述: Programming Assignment 2: Randomized Queues and Deques Write a generic data type for a deque and a randomized queue. The goal of this assignment is to implement elementary data structures using arrays and linked lists, and to introduce you to g

Mass assignment是rails中常用的将表单数据存储起来的一种方式.不幸的是,它的简洁性成了黑客攻击的目标.下面将解释为什么及如何解决. 上述表单为一个简单的注册表单.当用户填入name,点击提交时,一个新用户被创建.用户模型被如下定义: ruby create_table :users do |t| t.string :name t.boolean :admin, :default => false, :null => false end 当用户点击提交时,如下的action被执

题目链接:hdu4781 Assignment For Princess 题意:n个点m条边,每条有向边的权值分别是1,2,3…m,一个点能到达任意一个点,没有重边和自环,没有任何两条边的权值相同,任意一个有向环的权值和必须是3的倍数,现在需要把这个图输出来. 题解:注意到题目给出的范围m >= n+3,所以一定是可以构造出一个1~n的回路使得权值和为3的倍数的,可以让前n-1条边权值为1~n-1,第n条边(n->1)可以为n, n+1, n+2从而满足题意,后面再连任意两条不相邻的边时,边权

<Item 5> Know what functions C++ silently writes and calls 1.If you don't declare them yourself, compilers will declare their own versions of a copy constructor, a copy assignment operator, and a destructor. Furthermore, if you declare no constructo

POJ 3189 Steady Cow Assignment 题目链接 题意:一些牛,每个牛心目中都有一个牛棚排名,然后给定每个牛棚容量,要求分配这些牛给牛棚,使得所有牛对牛棚的排名差距尽量小 思路:这种题的标准解法都是二分一个差值,枚举下界确定上界,然后建图判断,这题就利用最大流进行判断,值得一提的是dinic的效率加了减枝还是是卡着时间过的,这题理论上用sap或者二分图多重匹配会更好 代码: #include <cstdio> #include <cstring> #inclu

Jimmy's Assignment Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 896    Accepted Submission(s): 379 Problem Description Jimmy is studying Advanced Graph Algorithms at his university. His most

Please follow the steps precisely in order to complete the objectives of the assignment. If you use the C++ FreeRTOS framework, it should make the assignment significantly easy. Create a producer task that takes 1 light sensor value every 1ms. Collec

注:命令行小写部分表出需要根据自己的情况改变!! a)激活SDSF资源类 SETROPTS CLASSACT(SDSF) b)查看SDSF资源类的PROFILE RLIST SDSF * c)如果不存在GROUP.ISFUSER.servername的PROFILE,则需要定义, RDEFINE SDSF (GROUP.ISFUSER.servername) OWNER(userid or group name) UACC(READ) 这样,所有用户都可以有读取权限,就都可以访问SDSF了 附1

问题:程序报错:local variable 'e' referenced before assignment 解决:遇到这样的问题,说明你在声明变量e之前就已经对其进行了调用,定位到错误的地方,对变量进行重新的声明 通常这样的问题对于python的程序员来说都是因为习惯了python2的语法,转移到python3中时,出现的错误.在Python3中,异常对象无法在异常块作用域外访问.(原因是在垃圾收集器运行且从内存中清理引用之前会在内存栈帧中保存一个引用周期)通常参考下面这个例子来做异常处理:

Assignment Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 297    Accepted Submission(s): 152 Problem Description Tom owns a company and he is the boss. There are n staffs which are numbered fro