Brief: the-ith-element,given a array A with n element , return the i-th element of A. A(n,i)
this problem can be solved using quick-sort idear, every time we choose a pivot ,after rearrangement, we know the pivot is the i-th element of A, so we can fixed this problem as the follow action.
i) choose pivot, rearrangement array, get the pivot index of j;
ii) if j > i , then recursion the 1-th partition , A(1-th , i);
iii)if j < i, then recursion the 2-th partition, A(2-th, i-j);
int element(int *array, int left, int right, int index) { if(left >= right) return array[left]; int pivot = array[left]; int i=0, j = 0; for(i=left+1,j = left+1; j <=right; ++j) { if(array[j] < pivot) swap(array[i++], array[j]); } swap(array[left], array[i-1]); //pivot is the (i-left)-th element, and pivot‘s index is i-1 if(index == i-left) return array[i-1]; else if(index < i-left) return element(array, left, i-2, index); else return element(array, i,right, index-i+left); }
时间: 2024-12-08 05:33:38