problem:
Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
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题意:输出1~n的 k 个数字的所有排列组合
thinking:
(1)看到题就应想到用DFS深搜法
(2)深搜的难点在于下一步怎么处理,这里开一个K大小的数组,记录深搜的每一步获取的数字
(3)时间复杂度为O(K*N),空间复杂度为O(k)
code:
class Solution { private: vector<vector<int> > ret; vector<int> tmp; public: vector<vector<int> > combine(int n, int k) { ret.clear(); tmp.resize(k); dfs(1,n,k,1); return ret; } protected: void dfs(int dep, int n, int k,int start) { if(dep>k) { ret.push_back(tmp); return; } for(int i=start;i<=n;i++) { tmp[dep-1]=i; dfs(dep+1,n,k,i+1); } } };
时间: 2024-09-29 18:30:53