LeetCode——Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters 
, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,

Given s = "Hello World",

return 5.

中文:给定一个字符串,包括大写/小写字母和空格字符,返回字符串中最后一个单词的长度。

假设最后一个单词不存在,返回0.

注意:一个单词被定义为仅包括非空字符的字符序列。

比如:

给定 s="Hello World",

返回 5.

此题可能是leetcode上面的最简单的一道题了。

Java:

	public int lengthOfLastWord(String s) {
		if(s.trim().equals(""))
			return 0;
        String[] str = s.split("\\s+");
        int len = str.length;
        return str[len-1].length();
    }

LeetCode——Length of Last Word

时间: 2024-10-09 13:23:54

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