Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering: 0.1 < 1.1 < 1.2 < 13.37
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解题思路:
(1)使用splt(“\\.”)对应小数点进行分离,然后逐个比较
(2)比较过程中,我们假定数组的长度一致。长度较短的数组,当比较到最后一个元素以后,往后自动加0操作
代码如下:
public static int Version(String version1, String version2) { //使用分隔符,然后进行比较 String[] str1=version1.split("\\."); String[] str2=version2.split("\\."); //获取需要比例的长度为两版本中长度的大者 int length=Math.max(str1.length, str2.length); for (int i = 0; i < length; i++) { /* * 下面两行代码的意思将两版本的长度设置成一样 * 如version1=1.1 version2=1.1.2 * 执行完 int num1=i<str1.length?Integer.parseInt(str1[i]):0 后 * version1=1.1.0,这样方便比较 */ int num1=i<str1.length?Integer.parseInt(str1[i]):0; int num2=i<str2.length?Integer.parseInt(str2[i]):0; if (num1>num2) { return 1; } else if (num1<num2) { return -1; } } return 0; }
时间: 2024-10-13 04:27:45