range的使用:注意,在python3中,交互模式下已经不显示了
for循环的使用
打印50-70
# 第一种方案 for i in range(100): if i <= 70 and i >= 45: #注意这里使用的是 and/or/not 非java中的&&,||,! print (i) # 第二种方案 for i in range(50,71): print (i)
break/continue的使用
exit_Flag = False for i in range(100): if i < 5: continue print("L_1:",i) for j in range(10): print("layer2:",j) if j == 7: exit_Flag=True break if exit_Flag: break
用户登录小程序
_user="hhh" _pass="hello" count = 1 while count <= 3: username = input("Please input the username:") password = input("Please input the password:") if _pass == password and _user == username: print("Welcome to BBT,", username) break else: print() print("Invalid username or password,you still have " + str(3 - count) + " times") count += 1 else: print("Time out,~-~")
原文地址:https://www.cnblogs.com/ftl1012/p/9381817.html
时间: 2024-10-20 03:56:11