2019 ICPC Malaysia National G(拓扑排序)

2019 ICPC Malaysia National G

有点绕，两层拓扑排序。

有空再补详细。

甚至有点丑，因为绕，为了区分，当时变量名写得很长。

#include<cstdio>
#include<algorithm>
#include<cstring>
#include<queue>
#include<vector>
#define debug printf("!")
using namespace std;
typedef __int64 ll;
const int mod=1e9+7;
const int maxn=2e4+5;
const int inf=0x3f3f3f3f;

int main()
{
    int m,n,u,v,i,j,k,l,y,r,e;
    int K[maxn];
    ll Q[maxn]={0};
    vector<int> pointtextdepend[maxn][110];
    vector<int> pointdepend[maxn];
    vector<int> pointtextque[maxn];
    vector<int> pointque;
    int In[maxn]={0};
    int textqua[maxn][110][2];
    scanf("%d%d",&n,&m);
    for(u=1;u<=n;u++)
    {
        int in[110]={0};
        scanf("%d",&k);K[u]=k;
        for(i=1;i<=k;i++)
        {
            scanf("%d",&l);
            for(j=1;j<=l;j++)
            {
                scanf("%d",&y);
                pointtextdepend[u][i].push_back(y);
                in[y]++;
            }
            scanf("%d%d",&textqua[u][i][0],&textqua[u][i][1]);
            if(textqua[u][i][0])
            {
                pointdepend[u].push_back(textqua[u][i][1]);
                In[textqua[u][i][1]]++;
            }
        }
        queue<int>q;
        for(i=1;i<=k;i++)
            if(in[i]==0)q.push(i);
        while(!q.empty())
        {
            int p=q.front(); q.pop();
            pointtextque[u].push_back(p);
            for(int i=0;i<pointtextdepend[u][p].size();i++)
            {
                y=pointtextdepend[u][p][i];
                in[y]--;
                if(in[y]==0)
                    q.push(y);
            }
        }
    }
    queue<int>q;
    for(i=1;i<=n;i++)
        if(In[i]==0) q.push(i);
    while(!q.empty())
    {
        int p=q.front(); q.pop();
        pointque.push_back(p);
        for(i=0;i<pointdepend[p].size();i++)
        {
            y=pointdepend[p][i];
            In[y]--;
            if(In[y]==0)
                q.push(y);
        }
    }
    for(v=n-1;v>=0;v--)
    {
        u=pointque[v];
        ll ans=0;
        ll textcaltime[110]={0};
        for(i=K[u]-1;i>=0;i--)
        {
            ll x,y=0;
            if(textqua[u][pointtextque[u][i]][0])x=(Q[textqua[u][pointtextque[u][i]][1]]+1)%mod;
            else x=textqua[u][pointtextque[u][i]][1];
            if(pointtextdepend[u][pointtextque[u][i]].size()==0)
            {
                textcaltime[pointtextque[u][i]]=x%mod;
                ans=max(ans,x)%mod;
                continue;
            }
            for(j=0;j<pointtextdepend[u][pointtextque[u][i]].size();j++)
            {
                y=max(y,(ll)textcaltime[pointtextdepend[u][pointtextque[u][i]][j]]);
            }
            textcaltime[pointtextque[u][i]]=(x+y)%mod;
            ans=max(ans,(x+y)%mod);
        }
        Q[u]=ans;
    }
    for(i=1;i<=m;i++)
    {
        scanf("%d",&v);
        printf("%I64d\n",Q[v]);
    }
}

2019-09-06

原文地址：https://www.cnblogs.com/kkkek/p/11470637.html